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3 years ago

Solve for x in the equation X^2 - 8X + 41= 0

Mathematics

1 answer:

BaLLatris [955]3 years ago

8 0

Answer:

The equation has two solutions for x:

x₁ = (8 + 10i)/2

x₂ = (8 - 10i)/2

Step-by-step explanation:

Let's use the quadratic formula for solving for x in the equation:

X^2 - 8X + 41= 0

x² - 8x + 41 = 0

Let's recall that the quadratic formula is:

x = -b +/- (√b² - 4ac)/2a

Replacing with the real values, we have:

x = 8 +/- (√-8² - 4 * 1 * 41)/2 * 1

x = 8 +/- (√64 - 164)/2

x = 8 +/- (√-100)/2

x = 8 +/- (√-1 *100)/2

Let's recall that √-1 = i

x = 8 +/- 10i/2

x₁ = (8 + 10i)/2

x₂ = (8 - 10i)/2

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Answer:

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Step-by-step explanation:

The picture of the question in the attached figure

step 1

Let

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step 3

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Convert to function notation

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Step-by-step explanation:

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