Question

Find the solution of the system of equations 2x-4y=32 2x-8y=48

Answer 1

2x-4y=32
2x-8y=48
--------------subtract
4y = - 16
y  = -4

2x-4y=32 
2x- 4(-4)=32 
2x + 16 = 32
2x = 16
x = 8

answer
(8, -4)

Answer 2

2x - 4y = 32
2x - 8y = 48

Multiple equation 2 by -1 so the 'x' variables will cancel.
-1(2x - 4y = 32)
-2x + 4y = - 32
 2x - 8y = 48
-------------------- add
     - 4y = 16      divide both sides by -4
         y = -4
Plug -4 back into either equation and solve for y.
2x - 4y = 32
2x -4(-4) = 32
2x + 16 = 32  subtract 16 from both sides
2x = 16          divide both sides by 2
x = 8
(8, -4)