First, we must understand what standard form of a line is. Standard form of a line is written like such that A,B, and C are all integers, and A must be positive. First, we must calculate the slope of the line that passes through theses coordinates.
<span>As a refresher, this is the equation to figure out the slope of two coordinates.Now, we just simplify the numerator and denominator. <span> </span></span>
The next step is to utilize point-slope form, which is where is a point on the line. Of course, we already know that (7,-3) and (4,-8) both lie of the line. Therefore, plug in one fot he coordinates. Once converted into point-slope, we must then convert into standard form. This is what is demonstrated in the next step.
<span>Let's multiply all sides by 3 to get rid of the fraction early.Distribute the 5 to both terms in the parentheses.Subtract 9 from both sides.Subtract 5x on both sides.We aren't done yet! The coefficient of the x-term must be positive. Therefore, divide by -1 on both sides.<span>This is standard form now, so we are done!</span></span>
if those r coordinates you can use the Pythagorean the to find the distance
plot the point and create a right triangle with the origin
could up the spaces and depending on the number, subtract the side from the hypotenuse or add the sides to find the hypotenuse
then square root both sides
<h3>Given</h3>
Two positive numbers x and y such that xy = 192
<h3>Find</h3>
The values that minimize x + 3y
<h3>Solution</h3>
y = 192/x . . . . . solve for y
f(x) = x + 3y
f(x) = x + 3(192/x) . . . . . the function we want to minimize
We can find the x that minimizes of f(x) by setting the derivative of f(x) to zero.
... f'(x) = 1 - 576/x² = 0
... 576 = x² . . . . . . . . . . . . multiply by x², add 576
... √576 = x = 24 . . . . . . . take the square root
... y = 192/24 = 8 . . . . . . . find the value of y using the above equation for y
The first number is 24.
The second number is 8.
Answer:
(-2,1) (-3,0)
Step-by-step explanation:
It hits on the line
