(8x 2 −15x)−(x 2 −27x)=ax 2 +bxleft parenthesis, 8, x, squared, minus, 15, x, right parenthesis, minus, left parenthesis, x, squ
quester [9]
Answer:
<h2>5</h2>
Step-by-step explanation:
Given the expression (8x² −15x)−(x² −27x) = ax² +bx, we are to determine the value of b-a. Before we determine the vwlue of b-a, we need to first calculate for the value of a and b from the given expression.
On expanding the left hand side of the expression we have;
= (8x² −15x)−(x² −27x)
Open the paranthesis
= 8x² −15x−x²+27x
collect the like terms
= 8x²−x²+27x −15x
= 7x²+12x
Comparing the resulting expression with ax²+bx
7x²+12x = ax²+bx
7x² = ax²
a = 7
Also;
12x = bx
b =12
The value of b - a = 12 - 7
b -a = 5
Hence the value of b-a is equivalent to 5
Answer:
1 neither
2 supplementary
3 supplementary
Step-by-step explanation:
the answer is D.
I dont know how to add work for a question like this, however, I know how I'd show work....
Draw a graph and stick a point in the IV quadrant and label it "original". Then next to it, draw another graph and stick a point in the III quadrant and label it "reflection"
TIP: if you do that, make sure the points are in the same location in each quadrant
Answer:
(6)
<u>Isosceles trapezoid</u>
- ∠R and ∠S are supplementary
- ∠S≅∠T, ∠R≅∠V
- m∠S = m∠T = 54°
- m∠R = 180° - 54° = 126°
(9)
<u>Midsegment is half the sum of the base lengths</u>
- ST = 1/2(FP + EQ)
- 3.1 = 1/2(2.7 + EQ)
- 2.7 + EQ = 6.2
- EQ = 6.2 - 2.7
- EQ = 3.5
