Answer:
x = 3 , y = -2
Step-by-step explanation:
Solve the following system:
{y = 1 - x | (equation 1)
y = 4 x - 14 | (equation 2)
Express the system in standard form:
{x + y = 1 | (equation 1)
-(4 x) + y = -14 | (equation 2)
Swap equation 1 with equation 2:
{-(4 x) + y = -14 | (equation 1)
x + y = 1 | (equation 2)
Add 1/4 × (equation 1) to equation 2:
{-(4 x) + y = -14 | (equation 1)
0 x+(5 y)/4 = (-5)/2 | (equation 2)
Multiply equation 2 by 4/5:
{-(4 x) + y = -14 | (equation 1)
0 x+y = -2 | (equation 2)
Subtract equation 2 from equation 1:
{-(4 x)+0 y = -12 | (equation 1)
0 x+y = -2 | (equation 2)
Divide equation 1 by -4:
{x+0 y = 3 | (equation 1)
0 x+y = -2 | (equation 2)
Collect results:
Answer: {x = 3 , y = -2
(rounded)