Using the discriminant determine the number of real solutions -4x^2+20x-25=0

Mathematics

2 answers:

seraphim [82]3 years ago

5 0

I think it's c I'm not too sure

Zepler [3.9K]3 years ago

5 0

Answer:

its c:two real solutions

Step-by-step explanation:

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A rectangular auditorium seats 1344 people. The number of seats in each rows exceeds the number of rows by 20. Find the number o

Tasya [4]

Let the number of rows be x

rows = x
seats in each row = x + 20

total seats = 1344
x (x + 20) = 1344
x^2 + 20x - 1344 = 0
(x + 48)(x - 28) = 0
x = -48 (rejected, answer cannot be negative) or x = 28

Therefore,
x = 28
x + 20 = 48

Check:
Row = 28
Numbers of seat per row = 28 + 20 = 48
28 x 48 = 1344 (Correct)

Ans:There are 48 seats per row

8 0

4 years ago

Solve the following equation. Then place the correct mixed number in the box provided. 5x/7=22

natka813 [3]

We have that
 5x/7=22
multiply by 7 both sides
5x=22*7-------> 5x=154
divide by 5 both sides
x=154/5
x=30.8--------> x=30 4/5

the answer is
x=30 4/5

7 0

3 years ago

A tree farm is building a greenhouse. Use the diagram to find the volume of the greenhouse

attashe74 [19]

Answer:

What diagram?

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Suppose that an angle is bisected to form two smaller angles that measure (2+30)° and (8+6)° . What is the measure of the origin

Valentin [98]

M<A=(2+30) M<B=(8+6)

(2+30)+(8+6)

32+14

M<A+B=46

Answer: The original angle measured 46 Degrees

6 0

3 years ago

8/x-5 - 9/x-4 = 5/x^2-9x+20

adelina 88 [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2752942

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Solve the equation:

$\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}$

Reduce the fractions at the left side so that they have the same denominator:

$\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}$

Numerators must be equal:

$\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}$

I hope this helps. =)

Tags: rational equation fraction solution algebra

7 0

3 years ago