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alukav5142 [94]
3 years ago
10

Using the discriminant determine the number of real solutions -4x^2+20x-25=0

Mathematics
2 answers:
seraphim [82]3 years ago
5 0
I think it's c I'm not too sure
Zepler [3.9K]3 years ago
5 0

Answer:

its c:two real solutions

Step-by-step explanation:


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the length of a side of the square is 4x-1. write a simplified expression that represents the perimeter of the square
Temka [501]
Answer: 16x - 4

Explanation: Since all of the sides of a square are equal in length by definition, the perimeter of a square is 4 times its side length. 4(4x-1) is 16x - 4 when simplified.
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Is multiplying proportional?
harina [27]

Answer:

yes in some cases

Step-by-step explanation:

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3 years ago
Use the graph of the function y = -x² + 2x + 8 to
Marianna [84]

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O-4 and 2

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7 0
2 years ago
Read 2 more answers
If a CONE has a DIAMETER of 10 centimeters and a Volume of 225 cubic centimeters, what is its approximate HEIGHT
ch4aika [34]

Answer:

The approximate height is 8.9 cm

Step-by-step explanation:

To find the height of a cone with a diameter of 10 cm and a volume of 225 cubic centimeter, we will follow the steps below;

first, write down the formula for finding the volume of a cone

v=πr²\frac{h}{3}

where v is the volume of the cone

r is the radius and h is the height of the cone

from the question given,

diameter = 10 cm   but       d=2r       this implies  that    r= \frac{d}{2}     r=   10/2   =    5cm

hence   r= 5cm

Also    v= 225 cm³

π  is a constant and is ≈ 3.14

We can now proceed to insert the values into formula and then solve for h

v=πr²\frac{h}{3}

225 ≈ 3.14 × 5² × \frac{h}{3}

225 ≈ 78.5 ×\frac{h}{3}

225 ≈ \frac{75.8 h}{3}

cross-multiply

675 = 75.8 h

divide both-side of the equation by 75.8

8.9 ≈ h

h≈ 8.9

Therefore, the approximate height is 8.9 cm

7 0
4 years ago
A child is crawling at a pace of 176 inches every 3.37 min. Provided that this child is able to maintain this same pace, how man
Mice21 [21]

The child crawled 18 meters in 823 seconds.

Given:

A child is crawling at a pace of 176 inches every 3.37 minutes.

To find:

The distance covered (in meters) by a child in 823 seconds.

Solution:

Distance covered by a child in 3.37 minutes = 176 inches

Distance covered by a child in a 1 minute =   \frac{176 inches}{3.37}

1 minute = 60 seconds

Distance covered by a child in 60 seconds =  \frac{176 inches}{3.37}

Distance covered by a child in a 1 second:

=\frac{176 inches}{3.37}\times \frac{1}{60}

Distance covered by a child in 823 seconds:

=\frac{176 inches}{3.37}\times \frac{1}{60}\times 823=716.36 inches

In 1 meter there are 39.37 inches.

1 meter=39.37 inches\\1 inches=\frac{1}{39.37} meters\\716.36 inches=\frac{716.36 inches}{39.37} m=18.1956 m\approx 18 m

The child crawled 18 meters in 823 seconds.

Learn more about the unitary method here:

brainly.com/question/19359186

brainly.com/question/20065206?referrer=searchResults

6 0
3 years ago
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