Answer : The limiting reactant is and the theoretical yield will be 86.45 grams.
Explanation : Given,
Moles of = 0.483 mole
Moles of = 0.911 mole
Molar mass of = 190 g/mole
First we have to calculate the limiting and excess reagent.
The given balanced chemical reaction is,
From the balanced reaction we conclude that
As, 2 moles of react with 1 mole of
So, 0.911 moles of react with
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of .
As, 2 moles of react to give 1 moles of
So, 0.911 moles of react to give
moles of
Now we have to calculate the mass of .
Therefore, the theoretical yield will be 86.45 grams.