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marysya [2.9K]
3 years ago
15

What happens to electrons in the photoelectric effect?

Chemistry
2 answers:
11111nata11111 [884]3 years ago
5 0
The photoelectric effect occurs when light shines on a metal. ... Light of any frequency will cause electrons to be emitted.
timofeeve [1]3 years ago
4 0

Answer:

Explanation:

Photoelectric effect was discovered in 1887 by Heinrich Rudolf Hertz. It refers to the ejection or emission of electrons when light hits a material (generally metal). Emitted electrons are called photo-electrons but the intensity of the light determine the kinetic energy of emitted electron.

Intensity of light is directly proportional to the kinetic energy emitted by an electron, that means more intensity the light have more will be the kinetic energy emitted by an electron.

You might be interested in
How many bromine atoms are present in 39.0 g of ch2br2?
Mandarinka [93]
Answer is: there is  2,69·10²³ atoms of bromine.
m(CH₂Br₂) = 39,0 g.
n(CH₂Br₂) = m(CH₂Br₂) ÷ M(CH₂Br₂).
n(CH₂Br₂) = 39 g ÷ 173,83 g/mol.
n(CH₂Br₂) = 0,224 mol.
In one molecule of CH₂Br₂, there is two bromine atoms, so:
n(CH₂Br₂) : n(Br) = 1 : 2.
n(Br) = 0,448 mol.
N(Br) = n(Br) · Na.
N(Br) = 0,448 mol · 6,022·10²³ 1/mol.
n(Br) = 2,69·10²³.
7 0
3 years ago
A train in Japan can travel 813.5 miles in 5 hours
Anastaziya [24]

Answer:

162.7miles/hr

Explanation:

Given parameters:

Distance covered by the train  = 813.5miles

Time taken  = 5hours

Unknown:

Speed of the train  = ?

Solution:

Speed is a physical quantity.

It is mathematically expressed as;

      Speed  = \frac{distance}{time}

So, input parameters and solve;

   Speed  = \frac{813.5}{5}  = 162.7miles/hr

8 0
3 years ago
How does an objects speed affect its kinetic energy?​
rewona [7]
Because it’s kinetic energy INCREASES the speed
8 0
3 years ago
What is mb for CH3NH2….
drek231 [11]

Answer:

A.) K_b = \frac{[CH_3NH_3^+][OH^-]}{[CH_3NH_2]}

Explanation:

The general Kb expression is:

K_b = \frac{[HA][OH^-]}{[A^-]}

In this equation

-----> Kb = equilibrium constant

-----> [HA] = acid

-----> [A⁻] = base

Since liquids are not included in equilibrium expressions, H₂O should not be present. The products are in the numerator while the reactant are in the denominator. In this reaction, CH₃NH₂ is acting as a base and CH₃NH₃⁺ is acting as an acid.

As such, the expression is:

K_b = \frac{[CH_3NH_3^+][OH^-]}{[CH_3NH_2]}

7 0
2 years ago
Consider the reaction:
goldfiish [28.3K]

Answer:

K = Ka/Kb

Explanation:

P(s) + (3/2) Cl₂(g) <-------> PCl₃(g) K = ?

P(s) + (5/2) Cl₂(g) <--------> PCl₅(g) Ka

PCl₃(g) + Cl₂(g) <---------> PCl₅(g) Kb

K = [PCl₃]/ ([P] [Cl₂]⁽³'²⁾)

Ka = [PCl₅]/ ([P] [Cl₂]⁽⁵'²⁾)

Kb = [PCl₅]/ ([PCl₃] [Cl₂])

Since [PCl₅] = [PCl₅]

From the Ka equation,

[PCl₅] = Ka ([P] [Cl₂]⁽⁵'²⁾)

From the Kb equation

[PCl₅] = Kb ([PCl₃] [Cl₂])

Equating them

Ka ([P] [Cl₂]⁽⁵'²⁾) = Kb ([PCl₃] [Cl₂])

(Ka/Kb) = ([PCl₃] [Cl₂]) / ([P] [Cl₂]⁽⁵'²⁾)

(Ka/Kb) = [PCl₃] / ([P] [Cl₂]⁽³'²⁾)

Comparing this with the equation for the overall equilibrium constant

K = Ka/Kb

5 0
3 years ago
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