Question

How many atoms of carbon are contained in 47.6 g of al2(co3)3? the molar mass of al2(co3)3 is 233.99 g/mol?

Answer 1

The molar mass of Al₂(CO₃)₃is 233.99 g/mol

It means 233.99 grams of Al₂(CO₃)₃ are in one mole

And moles in 47.6 g = 47.6/233.99 = 0.203 moles

Now we know that we have 0.203 moles of Al₂(CO₃)₃

In one mole of Al₂(CO₃)₃, we have 3 moles of carbon

To find the number of moles of carbon in a 0.203 moles of Al₂(CO₃)₃, we must multiply this by the 3 moles of carbon 

0.203 x 3 = 0.609 moles of carbon 

Within one mole of carbon, we have 6.022 x 10²³ atoms. So, to find the amount of atoms within 0.609 moles of carbon, we must multiply the 0.609 moles by 6.022 x 10²³ atoms. 

So, the number of carbon atoms present in 47.6g of Al₂(CO₃)₃ = 0.609 x 6.022 x 10²³ = 3.667 x 10²³ atoms.

Answer 2

$\boxed{3.667\times10^{23}\text{ atoms}}$  of carbon are present in 47.6 g of $\text{Al}_2\left(\text{CO}_3_\right)_3$.

Further Explanation:

Firstly, moles of $\text{Al}_2\left(\text{CO}_3_\right)_3$ that are present in 47.6 g of $\text{Al}_2\left(\text{CO}_3_\right)_3$ are to be calculated. This is done with the help of formula mentioned below.

The formula to calculate moles of $\text{Al}_2\left(\text{CO}_3_\right)_3$ is as follows:

$\text{Moles of Al}_2\left(\text{CO}_3_\right)_3=\dfrac{\text{Mass of Al}_2\left(\text{CO}_3_\right)_3}{\text{Molar mass of Al}_2\left(\text{CO}_3_\right)_3}$              ...... (1)

The mass of $\text{Al}_2\left(\text{CO}_3_\right)_3$ is 47.6 g.

The molar mass of $\text{Al}_2\left(\text{CO}_3_\right)_3$ is 233.99 g/mol.

Substitute these values in equation (1).

$\begin{aligned}\text{Moles of Al}_2\left(\text{CO}_3_\right)_3&=\dfrac{\text{47.6 g}}{\text{233.99 g/mol}}\\&=\text{0.203 mol}\end{aligned}$

From the calculated moles of $\text{Al}_2\left(\text{CO}_3_\right)_3$, moles of carbon that are present in $\text{Al}_2\left(\text{CO}_3_\right)_3$ can be calculated.

As is evident from the chemical formula of $\text{Al}_2\left(\text{CO}_3_\right)_3$, one mole of compound contains two moles of aluminum, three moles of carbon and six moles of oxygen in it.

Since one mole of $\text{Al}_2\left(\text{CO}_3_\right)_3$ contains three moles of carbon in it, number of moles of carbon in 0.203 moles of $\text{Al}_2\left(\text{CO}_3_\right)_3$ can be calculated as follows:

$\begin{aligned}\text{Moles of C}&=(\text{0.203 mol})\left(\dfrac{\text{3 mol}}{\text{1 mol}}\right)\\&=\text{0.609 mol}\end{aligned}$

In accordance with statement of Avogadro's law, one mole of any substance contains ${6.022\times 10^{23} \text{ particles}}$. Since one mole of carbon contains ${6.022\times 10^{23} \text{ atoms}}$ of carbon, number of carbon atoms in 0.609 moles of carbon can be calculated as follows:

$\begin{aligned}\text{Atoms of C}&=(\text{0.609 mol})\left(\dfrac{{6.022\times 10^{23} \text{ atoms}}}{\text{1 mol}}\right)\\&=3.667\times10^{23}\text{ atoms}\end{aligned}$

Learn more:

1. How many moles of Cl are present in 8 moles of $\text{CCl}_4$ ? brainly.com/question/3064603

2. Calculate the moles of ions in HCl solution: brainly.com/question/5950133

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Mole concept

Keywords: carbon, atoms, mole, molar mass, mass, Al2(CO3)3, 233.99 g/mol, 47.6 g, 0.203 mol, one mole, three moles, C, 0.609 mol, 3.667*10^23 atoms, Avogadro's law.