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Furkat [3]
4 years ago
5

The graph of f "(x) is continuous and decreasing with an x-intercept at x = 0. Which of the following statements is true?

Mathematics
1 answer:
kari74 [83]4 years ago
7 0

Answer:

The graph of f has an inflection point at x = 0.

Step-by-step explanation:

An inflection point occurs when the second derivative changes signs.  Since f"(x) is decreasing and has an x-intercept at 0, it changes signs from + to -, so there is an inflection point at x = 0.

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David pays $335 in advance on his account at the gym. Each time he visits the gym , $6 is deducted from the account. Write an eq
Korolek [52]

Answer:

x = 335 - (6 * v)

Step-by-step explanation:

In order to calculate the value remaining, we need to first multiply the daily cost of each visit by the number of visits made to the gym which is represented by the variable (v). Once we have this cost of all the days then we subtract this amount from the current account balance in order to get the new remaining balance which is represented by x.

x = 335 - (6 * v)

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It’s the last option (-6m-n+3)
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Pie

Answer:

• Slope is the derivative of the function:

{ \rm{f(x) =  {x}^{3}  + 3 {x}^{2} + 3x + 1 }} \\  \\ { \tt{ \frac{dy}{dx}  = 3 {x}^{2} + 6x + 3 + 0 }}

• At, x = 0

{ \tt{ \frac{dy}{dx}  = 3 {(0)}^{2}  + 6(0) + 3}} \\  \\ { \boxed{ \tt{slope = 3}}}

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Real solutions please WILL GIVE BRAINLIEST
Svetllana [295]

Answer:

the answer is A=2

Step-by-step explanation:

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I need help ASAP! It's urgent.. PLISSSSS​
natali 33 [55]

Answer:

a) 6 mins

b) 70km/h

c) t= 45

Step-by-step explanation:

a) The bus stops from t=10 to t=16 minutes since the distance the busvtravelled remained constant at 15km

Duration

= 16 -10

= 6 minutes

b) Average speed

= total distance ÷ total time

Total time

= 24min

= (24÷60) hr

= 0.4 h

Average speed

= 28 ÷0.4

= 70 km/h

c) Average speed= total distance/ total time

Average speed

= 80km/h

= (80÷60) km/min

= 1⅓ km/min

1⅓= 28 ÷(t -24)

<em>since</em><em> </em><em>duration</em><em> </em><em>for</em><em> </em><em>return</em><em> </em><em>journey</em><em> </em><em>is</em><em> </em><em>from</em><em> </em><em>t</em><em>=</em><em>2</em><em>4</em><em> </em><em>mins</em><em> </em><em>to</em><em> </em><em>t</em><em> </em><em>mins</em><em>.</em>

\frac{4}{3}(t -24)= 28

\frac{4}{3}t - 32= 28

\frac{4}{3}t= 32 +28

\frac{4}{3}t= 60

t= 6 0\div  \frac{4}{3}

t= 45

*Here, I assume that this is a displacement- time graph, so the distance shown is the distance of the bus from the starting point because technically if it is a distance-time graph, the distance would still increase as the bus travels the 'return journey'.

Thus, distance is decreasing after t=24 and reaches zero at time= t mins so that is the return journey. (because when the bus returns back to starting point, displacement/ distance from starting point= 0km)

5 0
4 years ago
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