Nathan launches a water balloon vertically from a platform on his roof. The height of the balloon (in feet) is represented by th
e equation h=−16t2+28.7t+32.4, where t is the time (in seconds) after he launches the water balloon. What is the maximum height of the balloon?
1 answer:
Answer:
45.27feet
Step-by-step explanation:
Given the height of the balloon (in feet) represented by the equation h=−16t2+28.7t+32.4, where t is the time (in seconds)
Note that the velocity of the balloon at maximum height is zero, hence;
v = dh/dt =0
-32t+28.7 = 0
-32t = -28.7
t = 28.7/32
t = 0.897secs
Get the maximum height
Recall that h=−16t²+28.7t+32.4
h = -16(0.897)²+28.7(0.897)+32.4
h= -12.87+25.74+32.4
h = 45.27feet
Hence the maximum height reached is 45.27feet
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#i'm from indonesia
hope it helps.