With any parallelogram, the diagonals bisect each other. This is another way of saying that they cut each other in half.
FH is one diagonal that is split into two equal pieces by the other diagonal EG.
The two parts of FH (KH and KF) are congruent to each other, so KH = KF. They combine back to FH
By the segment addition postulate
KH + KF = FH
KH + KH = FH .... KF has been replaced with KH (works because KF = KH)
2*KH = FH
Now use substitution
2*KH = FH
2*15 = FH .... replace KH with 15 (since KH = 15)
2*15 = 4x-2 ... replace FH with 4x-2 (since FH = 4x-2)
and solve for x
2*15 = 4x-2
30 = 4x-2
30+2 = 4x-2+2 ... add 2 to both sides
32 = 4x
4x = 32
4x/4 = 32/4 ... divide both sides by 4
x = 8
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Answer: x = 8
= 3x + 9x = 6x + 42
= 3x + 9x - 6x = 42 ( transposing +6x from LHS to RHS changes +6x to -6x )
= 12x - 6x = 42
= 6x = 42
= x = 42 ÷ 6 ( transposing ×6 from LHS to RHS changes ×6 to ÷6 )
= x = 7
Let us check whether we have found out the correct value of x or not by placing 7 in the place of x :
= ( 3 × 7 ) + ( 9 × 7 ) = 6 × 7 + 42
= 21 + 63 = 42 + 42
= 84 = 84
= LHS = RHS
Hence proved we have derived the correct value of x .
Therefore , the value of x = 7 .
Answer:
C. -20 and F. 20
Step-by-step explanation:
-20 x -20 = 400
20 x 20 = 400
Answer:
The coordinates of D are (2,-2)
Step-by-step explanation:
