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dimulka [17.4K]
4 years ago
12

Determine the length arc of JL

Mathematics
2 answers:
Novosadov [1.4K]4 years ago
7 0

Answer:59/12 pie

Step-by-step explanation:

I just took the test.

Paladinen [302]4 years ago
5 0

Answer:

The solution is

13

12

π.

Step-by-step explanation:

Arc Length=

m(ARC)

360

· 2πr

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If you have a rectangular bathtub, what would represent the volume?
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The amount of water that fills up the tub !
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A research study uses 800 men under the age of 55. Suppose that 30% carry a marker on the male chromosome that indicates an incr
ss7ja [257]

Answer:

a) There is a 12.11% probability that exactly 1 man has the marker.

b) There is a 85.07% probability that more than 1 has the marker.

Step-by-step explanation:

There are only two possible outcomes: Either the men has the chromosome, or he hasn't. So we use the binomial probability distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem, we have that:

30% carry a marker on the male chromosome that indicates an increased risk for high blood pressure, so \pi = 0.30

(a) If 10 men are selected randomly and tested for the marker, what is the probability that exactly 1 man has the marker?

10 men, so n = 10

We want to find P(X = 1). So:

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 1) = C_{10,1}.(0.30)^{1}.(0.7)^{9} = 0.1211

There is a 12.11% probability that exactly 1 man has the marker.

(b) If 10 men are selected randomly and tested for the marker, what is the probability that more than 1 has the marker?

That is P(X > 1)

We have that:

P(X \leq 1) + P(X > 1) = 1

P(X > 1) = 1 - P(X \leq 1)

We also have that:

P(X \leq 1) = P(X = 0) + P(X = 1)

P(X = 0) = C_{10,0}.(0.30)^{0}.(0.7)^{10} = 0.0282

So

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0282 + 0.1211 = 0.1493

Finally

P(X > 1) = 1 - P(X \leq 1) = 1 - 0.1493 = 0.8507

There is a 85.07% probability that more than 1 has the marker.

3 0
3 years ago
If ABCD is a parallelogram find the value of unknow size​
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Step-by-step explanation:

Hey, there!!

As it is a parallelogram, remember basic properties of parallelogram,

  • Their opposite sides are parallel and equal to eachother.
  • Their opposite angles are equal.
  • They have properties of parallel lines too.

Now, lets solve your question.

b = (7×10)°

Therefore, b= 70°.

now, (3x+10°)+b=180° { co- interior angle of a triangle sum is 180°}.

or, 3x= 180°-80°

or, x= 100°/3

Therefore, x= 33° { rounding off we get 33}.

w+ b =180°

w+70°=180° { coointerior angles are equal}.

Therefore, w =110°

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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X for the equations are:

1.-1.5
2.10
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