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denis-greek [22]
2 years ago
9

Glve the values of a, b, and c from the standard form of the equation (2x + 1)(x - 2) =0

Mathematics
1 answer:
Doss [256]2 years ago
4 0

Answer: Decimal- .33333333333

Fraction- 1/3

Step-by-step explanation: 3x-1=0

0+1=1, 1/3 is the answer

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D · 24 = -12<br> What does d equal?
Darya [45]

Answer: d=-1/2

<u>Move all terms to the left</u>

<u></u>d*24-(-12)=0<u></u>

<u></u>

<u>Add all the numbers together, and all the variables</u>

<u></u>d*24+12=0<u></u>

<u></u>

<u>Multiply elements</u>

<u></u>24d+12=0<u></u>

<u></u>

<u>Move all terms containing d to the left, all other terms to the right</u>

<u></u>24d=-12\\-12/24\\d=-1/2<u></u>

4 0
3 years ago
Read 2 more answers
Suppose brine containing 0.2 kg of salt per liter runs into a tank initially filled with 500 L of water containing 5 kg of salt.
Oliga [24]

Answer:

(a) 0.288 kg/liter

(b) 0.061408 kg/liter

Step-by-step explanation:

(a) The mass of salt entering the tank per minute, x = 0.2 kg/L × 5 L/minute = 1 kg/minute

The mass of salt exiting the tank per minute = 5 × (5 + x)/500

The increase per minute, Δ/dt, in the mass of salt in the tank is given as follows;

Δ/dt = x - 5 × (5 + x)/500

The increase, in mass, Δ, after an increase in time, dt, is therefore;

Δ = (x - 5 × (5 + x)/500)·dt

Integrating with a graphing calculator, with limits 0, 10, gives;

Δ = (99·x - 5)/10

Substituting x = 1 gives

(99 × 1 - 5)/10 = 9.4 kg

The concentration of the salt and water in the tank after 10 minutes = (Initial mass of salt in the tank + Increase in the mass of the salt in the tank)/(Volume of the tank)

∴ The concentration of the salt and water in the tank after 10 minutes =  (5 + 9.4)/500 = (14.4)/500 = 0.288

The concentration of the salt and water in the tank after 10 minutes = 0.288 kg/liter

(b) With the added leak, we now have;

Δ/dt = x - 6 × (14.4 + x)/500

Δ = x - 6 × (14.4 + x)/500·dt

Integrating with a graphing calculator, with limits 0, 20, gives;

Δ = 19.76·x -3.456 = 16.304

Where x = 1

The increase in mass after an increase in = 16.304 kg

The total mass = 16.304 + 14.4 = 30.704 kg

The concentration of the salt in the tank then becomes;

Concentration = 30.704/500 = 0.061408 kg/liter.

6 0
3 years ago
A electrician charges $45 per hour and spends $20 a day on gasoline.Write an algebraic expression to represent his earnings for
Sliva [168]
(45 X 24) - 20

hope this helps!
3 0
2 years ago
Read 2 more answers
-3x + 1 + 10x = x + 4<br><br> x = 12<br> x = 18
s344n2d4d5 [400]

-3x + 1 + 10x = x + 4

-3x +10x -x = 4 -1

6x = 3

x = 3/6

3 0
2 years ago
Tyler used 17.04 gallons of gas.Maria used 6.2 times as many gallon of gas as Tyler. How many gallons of gas did Maria use?
slava [35]
Tyler (T)= 17.04 gallons
Maria=6.2(T), Maria= 6.2x17.04=105.65 gallons
6 0
3 years ago
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