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qaws [65]
3 years ago
6

A​ city's mean minimum daily temperature in February is 22 degrees Upper F. Suppose the standard deviation of the minimum temper

ature in February is 5 degrees Upper F and that the distribution of minimum temperatures in February is approximately Normal. What percentage of days in February has minimum temperatures below freezing (32 degrees Upper F )​?
Mathematics
1 answer:
Rom4ik [11]3 years ago
3 0

Answer:

97.72%

Step-by-step explanation:

Given that a city's mean minimum daily temperature in February is 22 degrees Upper F, with std deviation 5 degrees.

Let X be the minimum temperature in February

Then X is N(22,5)

To calculate  percentage of days in February has minimum temperatures below freezing (32 degrees Upper F )

Probability that X <32 degrees

=P(Z

Convert this into percent by multiplying by 100

97.72% of days in February has minimum temperatures below freezing (32 degrees Upper F )​

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12 + x to the power of 4 - 6 when x = 8
iren [92.7K]

value of  12+x^4-6 at x=8 is  5002 .

<u>Step-by-step explanation:</u>

here we need to evaluate 12 + x to the power of 4 - 6 when x = 8 or , 12+x^4-6 where x=8 . Let's find out:

⇒ 12+x^4-6

Putting x =8 :

⇒ 12+8^4-6

Splitting 8 to power 4 into 8 to power 2 ( 2 times )

⇒ 12+8^2(8^2)-6

⇒ 12+64(64)-6

⇒ 12+4096-6

⇒ 4096+6

⇒ 5002

Therefore , value of  12+x^4-6 at x=8 is  5002 .

8 0
3 years ago
Is(5, 6)a solution to the inequality<br> y &lt; 2x + 4 ?
Diano4ka-milaya [45]

Answer:

yes

Step-by-step explanation:

y < 2x +4

6 < 2·5 +4

6 < 14

4 0
3 years ago
Which statement is true? Select all that apply.
julsineya [31]
It’s b and c and i believe a
3 0
3 years ago
HELP ASAP!!
garri49 [273]
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</span><span>y - x + 1 = 0
2 - 1 + 1 = 0
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</span><span>x - y + 1 = 0
1 - 2 + 1 = 0
0 = 0 correct

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Researchers investigated the possible beneficial effect on heart health of drinking black tea and whether adding milk to the tea
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Answer:

(a)  It is an experiment.

(b) Group III has been tested to compare the effect of tea

Step-by-step explanation:

24 volunteers are randomly selected to one of the three groups.

Group I drinks two cups of hot black tea without milk

Group II drinks two cups of hot black tea with milk

Group III drinks two cups of hot water but no tea.

At the end of the month, the researchers measured the change in each of the participant's heart health.

The average change of health status of three Groups can be measured and let it be X1', X2' and X3'. We can set up the hypothesis of no difference of heart health i.e H0 : µ1 = µ2 = µ3 against the alternative hypothesis that they are not equal. As the sample size is less than 30, we can use t-statistic.

Under the above logic, (a) it is an experiment.

(b) Group III has been tested to compare the effect of tea or to have comparison between GroupI and Group III.

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3 years ago
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