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qaws [65]
3 years ago
6

A​ city's mean minimum daily temperature in February is 22 degrees Upper F. Suppose the standard deviation of the minimum temper

ature in February is 5 degrees Upper F and that the distribution of minimum temperatures in February is approximately Normal. What percentage of days in February has minimum temperatures below freezing (32 degrees Upper F )​?
Mathematics
1 answer:
Rom4ik [11]3 years ago
3 0

Answer:

97.72%

Step-by-step explanation:

Given that a city's mean minimum daily temperature in February is 22 degrees Upper F, with std deviation 5 degrees.

Let X be the minimum temperature in February

Then X is N(22,5)

To calculate  percentage of days in February has minimum temperatures below freezing (32 degrees Upper F )

Probability that X <32 degrees

=P(Z

Convert this into percent by multiplying by 100

97.72% of days in February has minimum temperatures below freezing (32 degrees Upper F )​

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A room has an area of 216 square feet. One dimension is 6 feet more than the other. Find the length of the longer side.
zlopas [31]
The dimensions would be x and x+6. The area is 216.

x(x+6) = 216
x^2 + 6x - 216 = 0
(x-12)(x+18) = 0

x = 12---Yes---
x = -18---No, sides cannot be negative---

If one side is 12, the other side is 18. To check:

12 * 18 = 216
216 = 216

Correct
3 0
3 years ago
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Choose the equation that represents the graph below:
Zolol [24]
Y = x + 3 is the answer

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when you are trying to determine the gradient (the x), you can use two methods

first method:
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second method:
use the formula: (y - y) / (x - x)
So, you use the y from one of the brackets and subtract the y from the other bracket. Then, you put it over the x ,from the same bracket as the first y, and subtract the x from the second bracket. If you are confused, look at the picture. (Sorry for the messy explanation)

7 0
3 years ago
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After Michael finished his workout, his heart rate decreased by 100 beats per minute. If it took 10 minutes, on average how many
arsen [322]

Answer:

10

Step-by-step explanation:

8 0
3 years ago
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50 points
JulsSmile [24]

Answer:

b. w= 8x^2-2y / y

Step-by-step explanation:

Given:

(2*x^2)/y = (w+2)/4

Isolating w, we get:

w = (8*x^2)/y - 2  

Multiplying and dividing the second term in the right-side of the equality by y, we get:

w = (8*x^2)/y - 2*y/y  

Subtracting the fractions:

w = (8*x^2 - 2y)/y

7 0
3 years ago
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Only the circled ones
ozzi
2.

M must be (0,0) since it coincides with the origin
R must be (a+b, √(a²-b²)).
The x-coordinate is b from A translated to the right by a.
The y-coordinate is the same as A.

(I think the square root is there to confuse you).

3.

R(0,0)
C(a,b) (same x as T, same Y as E)

5.

Not sure how to prove that.

5 0
3 years ago
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