If point P partitions the segment AB in a 1:2 ratio, where is point P located?
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Answer:
C
Step-by-step explanation:
The red graph is the graph of y = f(x) shifted 1 unit right and then reflected in the x- axis.
Given y = f(x) then f(x + a) is a horizontal translation of a units
• If a > 0 then shift to the left of a units
• If a < 0 then shift to the right of a units
Here shift to the right of 1 unit, thus
y = f(x - 1)
Under a reflection in the x- axis
a point (x, y ) → (x, - y )
Note the y- coordinates are the negative of each other, thus
- y = f(x)
Now = - y, hence
The equation for the red graph is
= f(x - 1) → C