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malfutka [58]
3 years ago
9

What is an appropriate measure to record your weight?

Mathematics
1 answer:
Reil [10]3 years ago
6 0
That depends on where you live.  The purpose of writing down your
weight is often to tell other people what your weight is, so you want to
record it in units that the other people around you understand.

If you live in rural Scotland or Ireland, then you'd want to record it
in terms of stones and pounds.

If you live in Liberia, Myanmar, or the USA, then you'd probably
weigh yourself and record the results in pounds.

Anywhere in the rest of the world, it would be recorded in terms of kilograms.

You must be especially careful in the USA.  Here, you must not allow
any metric units to appear anywhere in your records, for if the eye of
an American should chance to fall on any written mention of a liter,
a meter, or a kilogram, the effect on his American physiognomy is
toxic.  His blood evaporates, his eyes turn backwards in their sockets,
and his abdomen falls out onto the floor.  Worst of all is the effect on
his brain.  It is well established now that having been born in the USA,
or after living there for some period of time, a person is incapable of
comprehending the metric system of units, so the rest of us must
protect them from it.
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Solve.<br> 4x+3y=5<br> 2x+3y=1<br><br> x=?<br> y=?
klasskru [66]

Answer:

x = 2, and y = -1. Point form: (2, -1)

Step-by-step explanation:

You solve the system of equations, by solving for one variable, and then subsitiute that variable into the other equation.

5 0
3 years ago
The following table gives annual life insurance premiums per $1,000 of face value. Use the table to determine the annual premium
Papessa [141]
The answer would be C !
4 0
2 years ago
Read 2 more answers
A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard
bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44

In point a)  

\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}

  = \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2

value= (1- \frac{1}{k^2}) \times 100 \% =75\%

In point b)

\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma  \\\\= |(x-\mu)|\leq 2.5 \times 4.44  \\\\  = |(x-\mu)|\leq 1.11 \\\\ =  (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)

In point c)

\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\

In point d)

using standard normal variate

x=20.17\\\\  z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17

8 0
3 years ago
What would happen to the perimeter of a shape when the dimensions are multiplied by 10
Mrrafil [7]

Answer:

Be 10 times larger.

Step-by-step explanation:

Imagine the perimeter is just 10. If it got 10 times larger, it goes to 100.

6 0
3 years ago
Did I do this correct???
kondor19780726 [428]
The answer is actually D. Since 2.5 is a side of each tiny block, there is 3 sides that you are going to multiply together. There is 5,2 and 4 because we are multiplying the length,width and side. So the length is 2.5*5=12.5 which was correct. The width is 2.5*4=10 which you had but you crossed it out. Then lastly you are looking for the side of the shape. 2.5*2=5. Now that I have everything I just need to multiply everything together. 12.5*10*5=625 in³. I hope this helped you! 
6 0
3 years ago
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