Answer:
17 in,3 in, and 19in
so the third answer
Step-by-step explanation:
Answer: <em><u>CAN YOU PLS MARK AS BRAINLIEST??</u></em>
a.x=11/4
b.x=6
c.x=21/2
d.x=0
Step-by-step explanation:
-2+3x+x=9-x
-2+3x+x=9
4x=9+2
4x=11
x=11/4
when you move a numerator to the other side it becomes a denominator
x+2=3/4x6
x+2=3/24
x=8-2
x=6
5-2x-12=14
2x=14-5+12
2x=21
x=21/2
1/2x=-3-1/2x+4-1
1/2x+1/2x=-3+4-1
x=0
<span>A dust particle weighs 7.42 × 10-10 kilograms.
Weight of 5 × 106 dust particles = </span>5 × 10^6 x 7.42 x 10^(-10)
= 5 x 7.42 x 10^(6-10)
= 37.1 x 10^(-4)
= 3.71 x 10^(-3) kilograms
For this case we must resolve the following inequality:

Applying distributive property on the left side of inequality we have:

Subtracting 5 from both sides of the inequality:

Subtracting 4x from both sides of the inequality:

Thus, the result is 
Answer:

The distance from Ship B to the signal fire at point C is 
Explanation:
It is given that two ships A and B are at a distance 140 ft from each other.
The angle formed by ship A is 82º and the angle formed by ship B is 78º.
To determine the distance from ship B to the signal fire at point C, we need to know the another angle.
Hence, we have,

Now, we shall solve the problem using the law of sines,

Substituting the values, we have,


Simplifying, we get,


Thus, the distance from Ship B to the signal fire at point C is 