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erastovalidia [21]
3 years ago
6

a) Let $\mathcal{R}$ be the region consisting of the points $(x,y)$ that satisfy \[-6 \le 3x - 5y \le 6\]and \[-3 \le x + 2y \le

3.\]Plot the region $\mathcal{R},$ and identify the vertices of polygon $\mathcal{R}.$ (b) Find the maximum value of $x + y$ among all points $(x,y)$ in $\mathcal{R}.$

Mathematics
2 answers:
jekas [21]3 years ago
8 0

Answer:

+ 2y \le 3.\]Plot the region $\mathcal{R},$ and identify the vertices of polygon $\mathcal{R}.$ (b) Find the maximum value of $x + y$ among all points $(x,y)$ in $\mathcal

Tems11 [23]3 years ago
6 0

First, we can solve the inequalities as if they were equalities, so we solve the equation 3x - 5y = -6 and x + 2y = 3.  Eliminating y, we get x = 3/11.  Then y = 15/11, so (x,y) = (3/11, 15/11) is one corner of the region R.  The inequalities are symmetric around the origin, so the region R is also symmetric around the region.  So R is the rectangle with vertices (-3/11, 15/11), (3/11, 15/11), (-3/11, 15/11), and (-3/11, -15/11).

The maximum value of x + y is then given by the corners of the rectangle R, so the maximum is 3/11 + 15/11 = 18/11.

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Charlotte spent 1/2 of the day shopping at the mall. She spent 1/4 of this time trying on jeans. What fraction of the days did C
Nadya [2.5K]

Answer:

1/8

Step-by-step explanation:

1/2 * 1/4 = 1/8

8 0
3 years ago
Read 2 more answers
Please help with these quick
drek231 [11]
To determine whether 10a-10c are true or false, you first need to know how to find the volume of the shoebox and the volume of the crate.

The equation for volume is l × w × h where l is the length, w is the width, and h is the height.

So, the volume of the shoebox is

V = l × w × h
V = 12 × 6 × 4
V = 288 cubic inches.

To find the volume of the crate, we simply multiply the volume of one shoebox by 20, as the crate holds 20 shoeboxes.

228 × 20 = 4560 cubic inches.

10a. Each shoebox has a volume of 22 cubic inches. <span>False. The volume is 228 cubic inches.

</span>10b. Each crate has a volume of about 440 cubic inches. <span>False. The volume of each crate is 4560 cubic inches.</span><span>

</span>10c. If the crate could hold 27 shoeboxes, the volume of the crate would be about 7,776 cubic inches.

For this one, let's do some more math. Since we figured out the volume of a crate holding 20 shoeboxes is 4560 cubic inches, let's do the same thing to find the volume of a crate holding 27 shoeboxes.

228 × 27 = 6156 cubic inches.

<span>False. The volume of a crate holding 27 shoeboxes would be 6156 cubic inches.

</span>11 part A:

Each term above describes the term below, but the term below doesn't necessarily describe the term above.

The choice of terms is : <span>trapezoid</span>, <span>triangle</span>, <span>rhombus</span>, <span>parallelogram</span>

Before we do anything else, let's define our terms, as well as the ones used in the diagram.

Trapezoid - A four sided shape with a pair opposite parallel sides.<span>
Triangle - </span>A shape with three sides.<span>
Rhombus - </span>A shape with four equal straight sides<span>.
Parallelogram - </span>A quadrilateral with two sets of parallel sides.<span>
Quadrilateral - </span>A four-sided shape with four angles.<span>
Square - </span>A four-sided shape with all four sides the same length, and all four angles are the same size.

The first term is quadrilateral. From this, we can determine that the term <span>triangle</span> won't be used at all, as it's a three-sided figure, whereas a <span>quadrilateral</span> is a four-sided figure. This leaves <span>trapezoid, rhombus, </span>and <span>parallelogram </span>as our terms.

A <span>trapezoid </span>is a <span>quadrilateral</span>, because it has four sides, but it can't be a <span>rhombus </span>or <span>parallelogram</span>, so it goes in the first open box.

A parallelogram is a trapezoid, because it has a pair of opposite parallel sides, but it can't be a rhombus, because it doesn't necessarily have all equal sides, so it goes in the second open box.

A rhombus is a parallelogram, because it has two sets of parallel sides, and goes in the third open box.

So, from top box to bottom box, the order the term go is
Quadrilateral
Trapezoid
Parallelogram
Rhombus
Square

3 0
3 years ago
Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif
algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64  

e) p_v =P(t_{118}  

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

\bar X_{O}=2.91 represent the mean for the Orange Coast

\bar X_{C}=2.96 represent the mean for the Coastline

s_{O}=0.05 represent the sample standard deviation for Orange Coast

s_{C}=0.03 represent the sample standard deviation for Coastline

n_{O}=60 sample size for Orange Coast

n_{C}=60 sample size for Coastline

\alpha=0.005 Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis:\mu_{O} \geq \mu_{C}  

Alternative hypothesis:\mu_{O} < \mu_{C}  

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=60+60-2=118  

Replacing the info we got:

t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64  

Part e

We can calculate the p value with this probability:

p_v =P(t_{118}  

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

5 0
3 years ago
Identify each figure in as many ways as possible
sattari [20]
Parallelogram
- quadrilateral (four sided figure)
- oposite sides parallel
<span>Rectangle
</span>- quadrilateral
- equiangular
<span>- right angle (90</span>° angle)<span>
Isosceles Trapezoid
</span>- quadrilateral
- pair of parallel sides
- called "trampezium" in the UK
<span>Square
</span>- regular quadrilateral
- equiangular
- right angles (90°)
5 0
3 years ago
Please can anyone help answer this question? It would be greatly appreciated!!! :)
Ray Of Light [21]

Answer:

0.667

Step-by-step explanation:

Angle in a circle = 360°

Area of total shaded parts = 60 + 60 = 120°

Area of total unshaded parts = 360-120 = 240°

Probability that a random selected point within the circle falls in the unshaded area

= 240/360

= 2/3

≈ 0.667

I apologize in advance if I made a mistake.

7 0
4 years ago
Read 2 more answers
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