Answer:
<h2>3(cos 336 + i sin 336)</h2>
Step-by-step explanation:
Fifth root of 243 = 3,
Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),
then r^5( cos Ф + i sin Ф )^5 = 243(cos 240 + i sin 240).
Equating equal parts and using de Moivre's theorem:
r^5 =243 and cos 5Ф + i sin 5Ф = cos 240 + i sin 240
r = 3 and 5Ф = 240 +360p so Ф = 48 + 72p
So Ф = 48, 120, 192, 264, 336 for 48 ≤ Ф < 360
So there are 5 distinct solutions given by:
3(cos 48 + i sin 48),
3(cos 120 + i sin 120),
3(cos 192 + i sin 192),
3(cos 264 + i sin 264),
3(cos 336 + i sin 336)
Answer:
100 :P when u read to fast n then put 2500 lol
Step-by-step explanation:
Slope for (x₁, y₁) and (x₂, y₂): (-3, 0) and (2, 7)
Slope: (y₂ -y₁) / (x₂ -x₁)
Slope: ( 7 - 0) / (2 - -3) = 7/(2 + 3)
<span>Slope = 7/5
</span>
Step-by-step explanation:
3/6=k/7
cross multiply then
6k=21
divide by the coefficient of k
k=3.5
