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3 years ago

12

PUTTING MAX POINTS

2 answers:

ra1l [238]3 years ago

7 0

Your answer should be d

svp [43]3 years ago

3 0

Your answer would be everything but (D) .

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A certain brand of candy is sold by weight with a 3 oz bag costing $0.75 if a bag of this candy costs $2.00 what does it weigh

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The answer is "8 ounces" I hope this helps

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3 years ago

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The endpoints of PQ are (4,1) and Q(4,8)

tatuchka [14]

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3 years ago

You invest 4,100 in an account that pays an interest rate of 7.25% ,compounded continuously. Calculate the balance of your accou

levacccp [35]

$\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount}
\\\\
A=Pe^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$4100\\
r=rate\to 7.25\%\to \frac{7.25}{100}\to &0.0725\\
t=years\to &8
\end{cases}
\\\\\\
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3 years ago

A^3+5-6(4)<br><br><br> HELP FAST I’M IN CLASS

zheka24 [161]

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3 years ago

It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken to estimate

Hitman42 [59]

Answer:

The minimum sample size is n = 75 so that the desired margin of error is 5 or less.

Step-by-step explanation:

We are given the following in the question:

Population variance = 484

Standard deviation =

$\sigma^2 = 484\\\sigma =\sqrt{484} = 22$

Confidence level = 0.95

Significance level = 0.05

Margin of error = 5

Formula:

Margin of error =

$E = z\times \dfrac{\sigma}{\sqrt{n}}\\\\n = (\dfrac{z\times \sigma}{E})^2$

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

Putting values, we get

$E\leq 5\\\\1.96\times \dfrac{22}{\sqrt{n}} \leq 5\\\\\sqrt{n} \geq 1.96\times \dfrac{22}{5}\\\\n \geq (1.96\times \dfrac{22}{5})^2\\\\n \geq 74.373$

Thus, the minimum sample size is n = 75 so that the desired margin of error is 5 or less.

3 0

2 years ago