<span> He could draw a diagram of a rectangle with dimensions x – 1 and x – 6 and then show the area is equivalent to the sum of x2, –x, –6x, and 6.</span>
x^2 + y^2 - 6x - 4y - 12 = 0
x^2 - 6x + y^2 - 4y = 12
x^2 - 6x + 9 + y^2 - 4y + 4 = 12 + 9 + 4
(x - 3)^2 + (y - 2)^2 = 25
<span>angle for JL and KL is <L
answer is C. L</span>
Answer:
the answer is 21 i know right