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Aleksandr-060686 [28]
3 years ago
15

Someone please help me on this math problem!

Mathematics
1 answer:
Galina-37 [17]3 years ago
3 0

Look at the picture.

Therefore we have the equation:

10y - 29 = 7y + 19       <em>add 29 to both sides</em>

10y = 7y + 48          <em>subtract 7y from both sides</em>

3y = 48      <em>divide both sides by 3</em>

y = 16



3x + 7 = 5x - 21            <em>subtract 7 from both sides</em>

3x = 5x = -28         <em>subtract 5x from both sides</em>

-2x = -28     <em>divide both sides by (-2)</em>

x = 14

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Find the value of X
geniusboy [140]
Here, angle (3x-1) is supplementary with 5x, so their sum would be equal to 180

3x - 1 + 5x = 180
8x = 180 + 1
x = 181/8
x = 22.625

Hope this helps!
8 0
3 years ago
What is the area and perimeter of the triangle ABH? How do I solve it? The process and answers? I am trying to help my 7th grade
n200080 [17]

Step-by-step explanation:

I dont remember perimeter but area is A= 1/2 bh

7 0
3 years ago
Find the value of the function f (x) = -3x + 17 for x = 5.
ss7ja [257]

Answer: 17/3

Step-by-step explanation:

7 0
3 years ago
Solve (16×^3-3×^2+43×-5)÷(×^2-2)
Oksana_A [137]

Answer:

3872/(x^2 - 2)

Step-by-step explanation:

Simplify the following:

(16^3 - 3^2 - 5×43)/(x^2 - 2)

3^2 = 9:

(16^3 - 9 - 5×43)/(x^2 - 2)

16^3 = 16×16^2:

(16×16^2 - 9 - 5×43)/(x^2 - 2)

| 1 | 6

× | 1 | 6

| 9 | 6

1 | 6 | 0

2 | 5 | 6:

(16×256 - 9 - 5×43)/(x^2 - 2)

16×256 = 4096:

(4096 - 9 - 5×43)/(x^2 - 2)

43 (-5) = -215:

(4096 - 9 + -215)/(x^2 - 2)

4096 - 9 - 215 = 3872:

Answer: 3872/(x^2 - 2)

7 0
3 years ago
Matt E. Matic was applying for a job. To determine whether he could handle the job, the personnel manager sent him out to poll 1
Rom4ik [11]

Answer:

No; he did the survey incorrectly.

He surveyed 107 people, not 100.

Step-by-step explanation:

Draw a Venn diagram, when you are presented with information like this;

Presenting it in a Venn diagram would look like what is shown in the pic.

P.S. when drawing a Venn diagram, start with the information regarding individuals who fit in all categories and then work your way to the individuals who fit in just in one category.

8 0
3 years ago
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