Answer:
16g of oxygen reacts with 2 g of hydrogen to form 18g of Water
Two electrons because it is in second group.
If a substance has a half-life of 39.1 min, and there are initially 20.0 g of the substance 2.39 g will remain after precisely two hours.
Solution:
N(t) = N0 (1/2)^t/t1/2
Nt = 20 (1/2)^120/39.1
Nt = 2.39 g
What is half life?
The time it takes for one-half of a radioactive isotope to decay is known as its half-life, and it is both an intriguing and practical feature of radioactive decay. An individual radioactive isotope's half-life is unaffected by environmental factors and is independent of the isotope's starting concentration.
N(t) = N0 (1/2)^t/t1/2
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Answer : The molar mass of unknown compound is 152.38 g/mole
Explanation :
Depression in freezing point =
Mass of unknown compound = 16.5 g
Mass of water = 106.0 g
Formula used :
where,
= depression in freezing point
i = Van't Hoff factor = 1 (for non-electrolyte)
= freezing point constant for water =
m = molality
Now put all the given values in this formula, we get
Therefore, the molar mass of unknown compound is 152.38 g/mole