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SCORPION-xisa [38]
2 years ago
5

water is formed when 48g of oxygen combine with 6g of hydrogen. what mass of oxygen combines with 2g of hydrogen

Chemistry
1 answer:
Mariulka [41]2 years ago
6 0

Answer:

16g of oxygen reacts with 2 g of hydrogen to form 18g of Water

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How many atoms are in Sodium, Carbon, Hydrogen, Oxygen, Fluorine, Boron, Lithium, Helium, Phosphorus and Sulfur?
vlada-n [284]
Sodium. 11
Carbon. 12
Hydrogen 1
Oxygen 2
Fluuorine. 14
Boron. 5
Lithium. 6
Helium 3
Phosphorus 15
Sulfur 6
6 0
3 years ago
Calculate the density of an object with a mass of 6.147 and a volume of 9.3 (include units)
Olin [163]
Here is the formula for density:
Density (D) = Mass (M) divided by Volume (V)

So you would do D = 6.147 divided by 9.3

As an as answer you would get: 0.6609677419g/cm^3

Additional information:

The formula for volume is:
V = M divided by D


The formula for Mass is:
M = D times V


I hope this helps :)
5 0
3 years ago
Which elements are solid at room temperature
Kryger [21]

Answer:bromine , neon , helium , argon , lithium , beryllium

Explanation:

8 0
3 years ago
A gas mixture contains 3.0 mol of hydrogen (H2) and 7.3 mol of nitrogen (N2). The total pressure of the mixture is 304 kPa. What
Inga [223]

Answer:

Mole fraction H₂ = 0.29

Partial pressure of H₂ → 88.5 kPa

Explanation:

You need to know this relation to solve this:

Moles of a gas / Total moles = Partial pressure of the gas / Total pressure

Total moles = 3 mol + 7.3 mol → 10.3 moles

Mole fraction H₂ → 3 moles / 10.3 moles = 0.29

Mole fraction = Partial pressure of the gas / Total pressure

0.29 . 304 kPa = Partial pressure of H₂ → 88.5 kPa

5 0
3 years ago
A student titrated 20 ml of 0.410 m hcl with 0.320 m naoh. determine the volume of naoh needed at equivalence point
Aleksandr-060686 [28]

Answer:

25.6mL NaOH

Explanation:

We are given the Molarity of the solution (\frac{moles}{liters}) and the volume of the solution (.02L).

By multiplying the two together, we can find the moles of solution that are reacted with HCl.

moles = \frac{.410 moles}{L} *.02L

This gives us .0082 moles of HCl.

We then find the moles of NaOH that are needed to react with the HCl using the equation.

HCl + NaOH = NaCl + H_{2} O

As HCl and NaCl have a 1:1 ratio, we need .0082 mol of NaOH.

Dividing this value by the Molarity of the solution

\frac{.0082mol}{.320mol/L}

Gives us the answer, in Liters (.0256), which we can then divide by 100 convert to mL.

3 0
2 years ago
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