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allochka39001 [22]
3 years ago
15

How many moles of NaOH are present in 27.5 mL of 0.270 M NaOH?

Chemistry
1 answer:
Naddik [55]3 years ago
8 0
The solution for the question above is:

C = 0.270 
<span>V = 0.0275L </span>
<span>n = ? </span>

<span>Use the molar formula which is: C = n/V </span>
<span>Re-arrange it to: n = CV </span>
<span>n = (0.270)*(0.0275) </span>
<span>n = 0.007425 mols </span>
<span>(more precise) n = 7.425 x 10^-3 mols
</span>
7.425 x 10^-3 mols is the answer.
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