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emmasim [6.3K]
3 years ago
9

1. Describe the difference between an electron and a proton in terms of their charge.​

Chemistry
1 answer:
Zarrin [17]3 years ago
5 0

Explanation:

Protons have a positive charge. Electrons have a negative charge. The charge on the proton and electron are exactly the same size but opposite. Neutrons have no charge.

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Aqueous sulfuric acid h2so4 will react with solid sodium hydroxide naoh to produce aqueous sodium sulfate na2so4 and liquid wate
Julli [10]
1) Balanced chemical equation

H2SO4 + 2NaOH ---> Na2 SO4 + 2H2O

=> 1 mol H2SO4 : 2 moles NaOH

2) Convert 89.3 g of H2SO4 and 96.0 g of NaOH to moles

Molar mass of H2SO4 = 98.1 g/mol

Molar mass of NaOH = 40.0 g/mol

moles = mass in grams / molar mass

moles H2SO4 = 89.3 g / 98.1 g/mol = 0.910 mol

moles NaOH = 96.0 g / 40.0 g/mol = 2.40 mol

3) Theoretical molar ratio = 2 moles NaOH / 1 mol H2SO4

So, all the 0.91 mol of H2SO4 will be consumed along with 1.820 (2*0.91) moles of NaOH, and 0.580 moles (2.40 - 1.82) of NaOH will be left over by the chemical reaction.

4) Convert 0.580 moles NaOH to mass

0.580 moles * 40.0 g/mol = 23.2 g of NaOH will be left over

6 0
3 years ago
Why is it so difficult
Sergeeva-Olga [200]
Because teachers don’t really understand it all that well themselves so they can’t teach it effectively
5 0
2 years ago
Read 2 more answers
In the reaction, A → Products, the rate constant is 3.6 × 10−4 s−1. If the initial concentration of A is 0.548 M, what will be t
Arada [10]

Answer:

        \large\boxed{\large\boxed{0.529M}}

Explanation:

Since the <em>rate constant</em> has units of <em>s⁻¹</em>, you can tell that the order of the reaction is 1.

Hence, the rate law is:

       r=d[A]/dt=-k[A]

Solving that differential equation yields to the well known equation for the rates of a first order chemical reaction:

      [A]=[A]_0e^{-kt}

You know [A]₀, k, and t, thus you can calculate [A].

       [A]=0.548M\times e^{-3.6\cdot 10^{-4}/s\times99.2s}

       [A]=0.529M

7 0
4 years ago
Rank the six combinations of electric charges on the basis of the electric force acting on q1. Define forces pointing to the rig
m_a_m_a [10]

Answer:

Explanation:

Let's define positive to be right. The net force on q2 is the

vector sum of the forces from q1 and q3.

The force has a magnitude of and points to the left.

Handling the signs correctly is critical. The negative signs

come from the direction of each of the forces (both to the left),

not from the signs of the charge.

2. Both charges 1 and 3 have 1 close

neighbor and 1 far neighbor. Will

they experience forces of the same

magnitude?

No, because both forces acting on charge 1 are in the same

direction, while the two forces acting on charge 3 are in

opposite directions. Thus, 1 > 3.

Both charges 1 and 2 have two forces acting in the same

direction. Will they experience forces of the same magnitude?

No, because one force acting on charge 1 is the same

magnitude as one acing on charge 2, while the second force

acting on charge 1 is smaller – it comes from a charge farther away

3 0
4 years ago
What is the correct way to represent the ionic compound sodium flouride
Dmitry [639]

The answer to that is: NaF

6 0
3 years ago
Read 2 more answers
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