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3 years ago

9

Nitrogen dioxide typically results from the oxidation of nitrogen monoxide in air. If 6.2 mols of N2 react, how many moles of NO

2 will be produced. Please show the work on how

1 answer:

xz_007 [3.2K]3 years ago

5 0

Answer: The mass of oxygen that combines with nitrogen will be 2.272g.

Explanation:

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Which of this is the method by which fire extinguisher works?

Andrew [12]

Answer:

the answer is a.cut off the supply of oxygen

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3 years ago

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HELPP!<br> how many grams are in 1.50 x 10(24) atoms of copper?

svlad2 [7]

Answer:

2266g

Explanation:

mass = no.of molecules /6.o23*1o(23) * molar mass

molar mass of co2= 44g /mol

1.5 .10^25/6.023 .10^23 =51.5 moles of co2

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3 years ago

2. (2 pts) How would you prepare 1.5 liters of 2 M KCI (MW=74.55 g/mol)

ra1l [238]

Answer:

Dissolve 226 g of KCl in enough water to make 1.5 L of solution

Explanation:

1. Calculate the moles of KCl needed

$n = \text{1.5 L} \times \dfrac{\text{2 mol}}{\text{1 L}}= \text{3.0 mol}$

2. Calculate the mass of KCl

$m = \text{3.0 mol} \times \dfrac{\text{74.55 g}}{\text{1 mol}}= \text{224 g}$

3. Prepare the solution

Measure out 224 g of KCl.
Dissolve the KCl in a few hundred millilitres of distilled water.
Add enough water to make 1.5 L of solution. Mix thoroughly to get a uniform solution.

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3 years ago

Can someone please please help me with this? I will mark you as brainlist? I only have two more questions but anyways

DENIUS [597]

Answer:

its 20 L

Explanation:

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. The freezing point of an aqueous solution containing a nonelectrolyte solute is – 2.79 °C. What is the boiling point of this s

Semmy [17]

Answer:

Boiling point of the solution is 100.78°C

Explanation:

This is about colligative properties.

First of all, we need to calculate molality from the freezing point depression.

ΔT = Kf . m . i

As the solute is nonelectrolyte, i = 1

0°C - (-2.79°C) = 1.86 °C/m . m . 1

2.79°C / 1.86 m/°C = 1.5 m

Now, we go to the boiling point elevation

ΔT = Kb . m . i

Final T° - 100°C = 0.52 °C/m . 1.5m . 1

Final T° = 0.52 °C/m . 1.5m . 1 + 100°C → 100.78°C

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3 years ago