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Katyanochek1 [597]
3 years ago
6

Solve each equation 4x=32​

Mathematics
2 answers:
siniylev [52]3 years ago
8 0
<h2>4x=32</h2><h2>x=32/4</h2><h2>x=8</h2>

FOLLOW ME FOR CLEARING YOUR NEXT DOUBT

geniusboy [140]3 years ago
6 0
Answer:
8

You can divide 32/4=8. So, x=8
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Answer:

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Step-by-step explanation:

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Easy question i will mark braineliest
Yuki888 [10]

Answer:

<h2>0.67</h2>

Step-by-step explanation:

5(y - 3.8) = 4.7(y - 4)

Distribute 5 through the parentheses

5y - 19 = 4.7(y - 4)

Distribute 4.7 through the parentheses

5y - 19 = 4.7y - 18.8

Move ' 4.7 y ' to L.H.S and change it's sign

5y - 4.7y - 19 =  - 18.8

Move constant to R.H.S and change it's sign

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Calculate

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Divide both sides of the equation by 0.3

\frac{0.3y}{0.3}  =  \frac{0.2}{0.3}

Calculate

y = 0.67

Hope this helps...

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3 0
3 years ago
Read 2 more answers
One company estimates same-day delivery as more than three less than half the total number of miles. Which
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Answer:

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Step-by-step explanation:

I took the quiz and got it right.

Also, the equation is y > x/2 - 3

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The triangle T has vertices at (-2, 1), (2, 1) and (0,-1). (It might be an idea to
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Rewrite the boundary lines <em>y</em> = -1 - <em>x</em> and <em>y</em> = <em>x</em> - 1 as functions of <em>y </em>:

<em>y</em> = -1 - <em>x</em>  ==>  <em>x</em> = -1 - <em>y</em>

<em>y</em> = <em>x</em> - 1  ==>  <em>x</em> = 1 + <em>y</em>

So if we let <em>x</em> range between these two lines, we need to let <em>y</em> vary between the point where these lines intersect, and the line <em>y</em> = 1.

This means the area is given by the integral,

\displaystyle\iint_T\mathrm dA=\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy

The integral with respect to <em>x</em> is trivial:

\displaystyle\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy=\int_{-1}^1x\bigg|_{-1-y}^{1+y}\,\mathrm dy=\int_{-1}^1(1+y)-(-1-y)\,\mathrm dy=2\int_{-1}^1(1+y)\,\mathrm dy

For the remaining integral, integrate term-by-term to get

\displaystyle2\int_{-1}^1(1+y)\,\mathrm dy=2\left(y+\frac{y^2}2\right)\bigg|_{-1}^1=2\left(1+\frac12\right)-2\left(-1+\frac12\right)=\boxed{4}

Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line <em>y</em> = 1 and (0, -1)), so its area is 1/2*4*2 = 4.

6 0
3 years ago
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