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kap26 [50]
3 years ago
15

Define a variable and the write an equation for the following problem. Then solve your equation and state your answer in a sente

nce. The number of student attending the fall play was 150 more than the number of adults attending. Student ticks cost $3 and adult tickets cost $5. A total of $4730 was collected. How many students attended the play?
Mathematics
1 answer:
AnnyKZ [126]3 years ago
8 0
If you need help I'll help you help help help
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Write as a multiplication sentence. 5/6 divided by 1 1/2
avanturin [10]

Write as a multiplication sentence.

5/6 divided by 1 1/2

Remember that

1 1/2=1+1/2=3/2

so

\frac{5}{6}\colon\frac{3}{2}=\frac{5}{6}\cdot\frac{2}{3}

7 0
1 year ago
EXAMPLE 5 If f(x, y, z) = x sin(yz), (a) find the gradient of f and (b) find the directional derivative of f at (1, 2, 0) in the
solong [7]

Answer:

<h2>a) f =  sin(yz)i + xzcos(yz)j + xycos(yz)k</h2><h2>b) -2</h2>

Step-by-step explanation:

Given f(x, y, z) = x sin(yz), the formula for calculating the gradient of the function is expressed as ∇f(x, y, z) = fx(x, y, z)i+ fy(x, y, z)j+fz(x, y, z)k where;

fx, fy and fz are the differential of the functions with respect to x, y and z respectively.

a) ∇f(x, y, z) = sin(yz)i + xzcos(yz)j + xycos(yz)k

The gradient of f =  sin(yz)i + xzcos(yz)j + xycos(yz)k

b) Directional derivative of f at (1,2,0) in the direction of v = i + 4j − k is expressed as ∇f(1, 2, 0)*v

∇f(1, 2, 0) = sin(2(0))i +1*0cos(2*0)j + 1*2cos(2*0)k

∇f(1, 2, 0) = sin0i +0cos(0)j + 2cos(0)k

∇f(1, 2, 0) = 0i +0j + 2k

Given v = i + 4j − k

∇f(1, 2, 0)*v (note that this is the dot product of the two vectors)

∇f(1, 2, 0)*v =  (0i +0j + 2k)*(i + 4j − k )

Given i.i = j.j = k.k =1 and i.j=j.i=j.k=k.j=i.k = 0

∇f(1, 2, 0)*v = 0(i.i)+4*0(j.j)+2(-1)k.k

∇f(1, 2, 0)*v = 0(1)+0(1)-2(1)

∇f(1, 2, 0)*v =0+0-2

∇f(1, 2, 0)*v= -2

 

Hence, the directional derivative of f at (1, 2, 0) in the direction of v = i + 4j − k is -2

7 0
3 years ago
The new building is 22.5 inches from the gymnasium in the model. What will be the actual
Len [333]

Answer:

67.5feet

Step-by-step explanation:

Given parameters:

Model distance between building and gymnasium  = 22.5 inches

Scale of model :  1 inch  = 3 feet

Unknown:

Actual ground distance  = ?

To solve this problem, we first must understand the concept of scale. A scale is a relationship that represents a dimension on a map/model compared to the true ground expression. In order to visualize or represent some real life objects on paper or in a computer, we use models. These models are an abstraction of the real world based on scales. There are different ways of representing a scale.

In this problem;

    the scale is given as;

                     1 inch on model  represents 3 feet on ground

Now, to find 22.5 inches, simply cross multiply and solve;

        If   1 inch on model  represents 3 feet on ground

              22.5 inches on a model  will be =  \frac{22. 5 inches x 3 feet }{1 inches}

                                                                   = 67.5feet

Therefore, the actual distance is 67.5feet

8 0
3 years ago
Which expression is equivalent to -36 – 8?
balandron [24]

Answer:

-36+-8=-44

Step-by-step explanation:

8 0
3 years ago
if one tray can hold 12 loaves of bread and eat your I can hold 10 trays can a hundred twenty-five Loaves fit on one rack
tia_tia [17]
I believe the wording of the question is: If one tray can hold 12 loaves of bread and the rack can hold 10 trays, can a hundred and twenty-five loaves fit on one rack? 
Then the answer would be, no. 
12 x 10 = 120

6 0
3 years ago
Read 2 more answers
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