Let x be the number of pens in a box.
Jill : three full boxes of pen and 2 loose pens. 3x + 2
Ben: two full boxes of pen and 14 loose pens. 2x + 14
Jill and Ben have the same pens.
Jill = Ben
3x+2 = 2x + 14
3x - 2x = 14 - 2
1x = 12
x = 12
To check:
Jill = Ben
3x + 2 = 2(x) + 14
3(12) + 2 = 2(12) + 14
36 + 2 = 24 + 14
38 = 38
There are 12 pens or a dozen of pens in a full box.
8n + 22 = 70
-22 -22
8n = 48
n = 48/8
n = 6
n*3 = 3n = 6*3 = 18
3n = 18
Answer: No
Step-by-step explanation: First, we need to understand that parallel lines are coplanar lines that do not intersect. On the other hand, perpendicular lines are lines that intersect at a right angle.
However, lines can't be both parallel and perpendicular because they either intersect each other at a right angle or never intersect.
So no, two lines can't be both parallel and perpendicular.
Answer:
21 matches
Step-by-step explanation:
This is a combination problem where we have to select two member out of 7 members
So we want calculation of 7C2
7C2 = 7!/[(2!)(7-2)!]
(7*6*5*4*3*2*1)/[(2*1) *(5*4*3*2*1]
(7*6)/2 ~ Note everything that easily cancels here!
42/2
21 matches
Answer:
i think it is 1
Step-by-step explanation:
