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Anna11 [10]
3 years ago
5

What is the answer to 5x-1=x+15

Mathematics
2 answers:
DanielleElmas [232]3 years ago
3 0
-- Add  1  to each side.

-- Then subtract 'x' from each side.

-- Finally, divide each side by  4, and the answer will jump out at you.
Ilya [14]3 years ago
3 0
5x - 1 = x + 15
subtract x to both sides
4x - 1 = 15
add 1 to both sides
4x = 16
divide 4 to both sides
x = 4 
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SUPER EASY WILL GIVE BRAINLEIST IF DONE BEFORE 10 PM PLS HURRY. IF U HAVE TIME PLS HELP ME ON OTHER QUESTIONS THANK YOU <3
andrew11 [14]

Answer:

1. new perimeter = 4 times the old perimeter

2. The area will go up by a factor of 16

3. The new area is 1/9 of the original area.

Step-by-step explanation:

1. side length1 = x

side length2 = y

2x + 2y = perimeter

2(4x) + 2(4)y = new perimeter

8x + 8y = new perimeter

new perimeter = 4 times the old perimeter

2. The area will go up by a factor of 16. This is because the area formula has them being multiplied together and thus it will make the area go up by that much.

3. Let the length of the rectangle be x

Let width of rectangle be y

Area of rectangle =  L*W

Now Each side length of the rectangle is multiplied by 1/3

So, new area =  (1/3)L * (1/3)W

=(1/9)LW

So, the new area is 1/9 of the original area.

7 0
3 years ago
Y = 3x - 5 what is the value of Y??
lara [203]

Answer:

41

Step-by-step explanation:

x=12

so y=3⋅12 +5

=36+5

=41

6 0
3 years ago
Read 2 more answers
Translate the following into an equation <br> “the sum of the number and three is fivem
guapka [62]

Answer:

n+3=5m

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Whats 567 divided by 566789
Doss [256]

0.00100037227 will be your correct answer.

7 0
3 years ago
If 1-cosA = 1/2 , Then find the value of sinA.
zimovet [89]

Step-by-step explanation:

Given :

1- cosA = 1/2

or, CosA = 1 -1/2

Therefore ; CosA = 1/2 = b/h

According to the Pythagoras theorem,

P = root under h^2 - b^2

= root under (2)^2 - (1)^2

= root under 4 -1

= root 3

Again,

SinA = P/h

= root 3 / 2

8 0
2 years ago
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