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3 years ago

For f(x)=4x+1 and g(x)=x^2-5 find (f-g)(x)

Mathematics

2 answers:

Marrrta [24]3 years ago

6 0

$f(x)=4x+1,\ g(x)=x^2-5\\\\(f-g)(x)=f(x)-g(x)\\\\\text{Therefore}\\\\(f-g)(x)=(4x+1)-(x^2-5)=4x+1-x^2+5=-x^2+4x+6$

almond37 [142]3 years ago

4 0

Answer:

x^2+4x-4

Step-by-step explanation:

This guy made me miss it so it gave me the answer

APEX

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2 years ago

Partial fraction decomposition<br> 20x+9/25x^2+20x+4

ozzi

Step-by-step explanation:

We have

$\frac{20x + 9}{25 {x}^{2} + 20x + 4 }$

Let's factor the denomiator first,

the denomaitor is a perfect square so we get

$\frac{20x + 9}{(5x + 2) {}^{2} }$

Now, we must think of two fractions that

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So right now, we have

$\frac{a}{(5x + 2) { }^{2} } + \frac{b}{5x + 2} = \frac{20x +9 }{25 {x}^{2} + 20x + 4 }$

$a + (5x + 2)b = 20x + 9$

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so that means that a is

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So our equation is

$\frac{1}{(5x + 2) {}^{2} } + \frac{4}{5x + 2}$

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2 years ago