Answer:
amount invest in B is 2000
Explanation:
given data
invested in Fund A = 5000
return profit A = 3%
return profit B = 10%
both together returned profit = 5%
solution
we consider here amount invest in B = x
so profit from fund B is
profit from fund B = 10% × x = 0.1 x
and
profit from fund A = 5000 × 3% = 150
so total profit = 0.1x + 150
and total profit = 5%
so we can say
5% = 
solve it we get
x = 2000
so amount invest in B is 2000
Answer:
AUD 39.93 is expected to be received for your baht.
Explanation:
To calcuate the cross currency exchange rate between Thai Baht and AUD, inverse the USD per Thai Baht quote, this will give you (1/0.023 = 43.478). Now, multiply this by USD per AUD ( TBHT by USD multiplied by USD by AUD, thus USD will cancel out and leave you with TBHT by AUD). The Final ER will stand at TBHT 25.0434 per AUD. Divide the sum of TBHT 1000 by 25.0434 and you will recieve AUD 39.93
Answer:
Life cycle assessment
Explanation:
Life cycle assessment is a technique that is used to analyse the environmental impacts of products from the design stage through end life. This assessment technique helps to examine the environmental impacts of products throughout their lives. It consists of 5 stages of material extraction, manufacturing, packaging and transportation, use and end of life. This analysis is carefully designed to effectively estimate the environmental impacts.
Answer:
the probability that exactly 8 complete the program is 0.001025
Explanation:
given information:
60 % of those sent complete the program, p = 0.6
the total of people being sent, n = 27
exactly 8 complete the program, x = 8
to find the probability, we can use the following formula
![P(X=x)=\left[\begin{array}{ccc}n\\x\\\end{array}\right] p^{x} (1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%3Dx%29%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dn%5C%5Cx%5C%5C%5Cend%7Barray%7D%5Cright%5D%20p%5E%7Bx%7D%20%281-p%29%5E%7Bn-x%7D)
![P(X=8)=\left[\begin{array}{ccc}27\\8\\\end{array}\right] 0.6^{8} (1-0.6)^{27-8}](https://tex.z-dn.net/?f=P%28X%3D8%29%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D27%5C%5C8%5C%5C%5Cend%7Barray%7D%5Cright%5D%200.6%5E%7B8%7D%20%281-0.6%29%5E%7B27-8%7D)
![P(X=8)=\left[\begin{array}{ccc}27\\8\\\end{array}\right] 0.6^{8} (0.4)^{19}](https://tex.z-dn.net/?f=P%28X%3D8%29%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D27%5C%5C8%5C%5C%5Cend%7Barray%7D%5Cright%5D%200.6%5E%7B8%7D%20%280.4%29%5E%7B19%7D)
= 0.001025