Question

HELP PLEASE !!!!!!! Pythagorean theorem

Answer 1

Answer:

$\large\boxed{x=8\sqrt3}$

Step-by-step explanation:

The Pythagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have:

$leg=8, leg=x,\ hypotenuse=16$

Substitute:

$8^2+x^2=16^2$

$64+x^2=256$        subtract 64 from both sides

$x^2=192\to x=\sqrt{192}\\\\x=\sqrt{(64)(3)}\\\\x=\sqrt{64}\cdot\sqrt3\\\\x=8\sqrt3$