Answer:
Y'=3xy-3x-12
Y'=F(-2,-1)=0
Step-by-step explanation:
The function of the equation at the point (-2,-1)
is where the equation make the function go to zero:
Y'=3xy-3x-12
Y'=F(-2,-1)=[3(-2)(-1)]-[3(-1)]-12
F(-2,-1)=[6]-[-6]-12
F(-2,-1)=6+6-12
F(-2,-1)=12-12
F(-2,-1)=0
Solving for y
3xy-3x-12=0
y=4/x+x
Making y=0



So the values make the function go to zero
It would be 32-4x=12
32-4(5)=12
32-20=12
12=12
13-9 = 4
4-4 = 0
0 divided by 2 = 0
2x = 0
x = 0
Answer:
Step-by-step explanation:
use pythagorean theorem a^2 + b^2 = c^2
a = 6, b = 8
6^2 + 8^2 = c^2
100 = c^2
c = -10
since it cant really be negative, the distance becomes 10.