f) 16 - p = 12 minus 12
4 - p = 0 plus p
p = 4
g) 18 - 2p = 6 divide by -2
-9 + p = -3 plus 9
p = 6
h) p x 2 + 4 = 9 divided by 2
p + 2 = 4.5 minus 2
p = 2.5
i) p x 4 - 3 = 1 plus 3
p x 4 = 4 divided by 4
p = 1
Let's start with triangle RST. This is a 30-60-90 triangle, which means it has the relationship x - x sqrt(3) - 2x.
If RS is 2 sqrt(3), then ST must be 2 and RT must be 4.
Triangle QRT is a 45-45-90 triangle, which means it has the relationship x - x - x sqrt(2).
If RT is 4, then RQ must also be 4.
Answer: x = 4
Hope this helps!
Answer:
1. A = 59
2. A = 43
Step-by-step explanation:
If we have a right triangle we can use sin, cos and tan.
sin = opp/ hypotenuse
cos= adjacent/ hypotenuse
tan = opposite/ adjacent
For the first problem, we know the opposite and adjacent sides to angle A
tan A = opposite/ adjacent
tan A = 8.8 / 5.2
Take the inverse of each side
tan ^-1 tan A = tan ^-1 (8.8/5.2)
A = 59.42077313
To the nearest degree
A = 59 degrees
For the second problem, we know the adjacent side and the hypotenuse to angle A
cos A = adjacent/hypotenuse
cos A = 15.3/21
Take the inverse of each side
cos ^-1 cos A = cos ^-1 (15.3/21)
A = 43.23323481
To the nearest degree
A = 43 degrees
