Question

Quick help guys thanks :)

Answer 1

Answer:

$\large\boxed{t^{-58}u^{-88}v^{-71}w^{-1}}$

Step-by-step explanation:

$\dfrac{tuv^4w^0}{t^{59}u^{89}v^{75}w}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=t^{1-59}u^{1-89}v^{4-75}w^{0-1}=t^{-58}u^{-88}v^{-71}w^{-1}$