Question

PLZZZ ANSWER ASAP

Answer 1

Any straight line on the coordinate plane can be described by the equation

y=mx+b

Where:

x,y are the coordinates of any point on the line

m is the slope of the line

b is the intercept (where the line crosses the y-axis)  .

The slope m can be found beetween two points on the line:

$(x_1,y_1)$ and $(x_2,y_2)$

$m=\frac{y_2-y_1}{x_2-x_1}$

In this case, the points is on the y-axis (0,300) and the x-axis (450,0), whereby the slope m is found:

$m=\frac{y_2-y_1}{x_2-x_1} = \frac{0-300}{450-0} = -\frac{2}{3}$

We already have b, because b is the point, where the line crosses the y-axis.

b=300

So the equation is:

$m=-\frac{2}{3} \\b=300\\y=mx+b$ ⇒ $y=-\frac{2}{3} +300$

The graph is attached.