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Nikitich [7]
3 years ago
12

Jack owes a total of $24.00 to 6 different friends. If Jack owes each friend an equal amount, which answer choice represents the

change in Jack's money when he pays one friend?
Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
6 0

Answer:

5555555555555555555225313

Step-by-step explanation:

3

6

554

mart [117]3 years ago
4 0

Answer:

$20.00

Step-by-step explanation:

24.00/6=4 so 24-4=20.00

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Ms. Lui earned an annual income of 775,000, what is the weekly salary?
jok3333 [9.3K]

Answer:

$14,903.85

Step-by-step explanation:

So, Ms. Lui earns $775,000 each year. To find the weekly salary, we have to divide the annual income by the amount of weeks in a year. There are about 52 weeks in one year. Let's find the weekly salary:

\frac{775000}{52} = 14,903.85

Therefore, Ms. Lui earns $14,903.85 a week.

Hope this helps! If you have questions about my work, please leave them in the comments!

4 0
2 years ago
Write the subraction problem 604-357. describe how you will subtract to find the difference
andre [41]
First you will subtract right to left and then what ur left with is the sum.
3 0
4 years ago
Read 2 more answers
Laquita practiced 60 math facts. Kinman practiced 15 more facts than Laquita. How many math facts did they practice in all?
Afina-wow [57]

Answer:

They practiced a total of 75 math facts in all!

60 + 15 = 75 :D

5 0
3 years ago
Find the general solution of the following ODE: y' + 1/t y = 3 cos(2t), t > 0.
Margarita [4]

Answer:

y = 3sin2t/2 - 3cos2t/4t + C/t

Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

I = t

The general solution for first a first order DE is expressed as;

y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.

yt = ∫t(3cos2t)dt

yt = 3∫t(cos2t)dt ...... 1

Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt

= tsin2t/2 - cos2t/4 ..... 2

Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

y = 3sin2t/2 - 3cos2t/4t + C/t

Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t

3 0
3 years ago
A home has dimensions of 35 feet by 57 feet that include an attached 24-foot by 22-foot garage and a 200-square-foot screened po
tekilochka [14]
35*57 = 1995
1995 - ((24*22)+200) = 1267
1267 is your answer.
8 0
3 years ago
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