(-5,7) Quadrant 2
(5,-18) Quadrant 4
(10,6) Quadrant 1
(-6,-4) Quadrant 3
(-2,6) Quadrant 2
(2,-6) Quadrant 4
(-10,-13) Quadrant 3
(-4,0) x axis
(0,5) y axis
Answer:
be rewritten as a square of a sum
Step-by-step explanation:
The value of x in x^yz = y^2 is ![x = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
<h3>How to solve for x?</h3>
The equation is given as:
x^yz = y^2
Rewrite the equation properly as follows

Take the yz root of both sides
![\sqrt[yz]{x^{yz}} = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=%5Csqrt%5Byz%5D%7Bx%5E%7Byz%7D%7D%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Apply the law of indices
![x^{\frac{yz}{yz}} = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Byz%7D%7Byz%7D%7D%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Divide yz by yz
![x = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Hence, the value of x in x^yz = y^2 is ![x = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Read more about equations at:
brainly.com/question/2972832
#SPJ1
Answer:
You are clicking on graphs.
However, you should sketch a graph of your function to see what the correct one looks like.
Create a table containing a few values of x and y
I chose x = -4, -2, 0, 2, 4.
Draw your axes
Plot your points
Draw the graph
Your graph should look like the one below.
Step-by-step explanation: