Answer:
$7.9 /hour
Step-by-step explanation:
$316/40 = $7. 9per hour
9514 1404 393
Answer:
15
Step-by-step explanation:
In vector form, the equation of point p on the line can be written as ...
p = (-3, -4) +t(25 -(-3), 38 -(-4)) . . . . . for some scalar t
p = (-3, -4) +t(28, 42)
p = (-3, -4) +14t(2, 3)
where t takes on any value between 0 and 1.
If we let t = n/14 for some integer 0 ≤ n ≤ 14, then the coordinates of point p will be integers.
There are 15 values that n can have in the allowed range.
The caterpillar touches 15 points with integer coordinates.
Answer:
AECG
Step-by-step explanation:
1
sqrt(49) = 7
sqrt(a^2) = a
sqrt(b^2) = b
For every two variables you can take one out from under the root sign and thorough the other one away.
Answer: E
2
sqrt(36) = 6
sqrt(a^2) = a See comment for 1.
b must be left where it is. There is only 1 of them.
6asqrt(b)
Answer: A
3. sqrt(25) = 5
sqrt(b^2) = b
a must be left alone. There's only 1 of them.
5b sqrt(a)
answer: C
4
sqrt(81 a b)
sqrt(81) = 9
The variables must be left alone. There's only1 of them
9 sqrt(ab)
Answer G
Answer:
Step-by-step explanation:
A1. C = 104°, b = 16, c = 25
Law of Sines: B = arcsin[b·sinC/c} ≅ 38.4°
A = 180-C-B = 37.6°
Law of Sines: a = c·sinA/sinC ≅ 15.7
A2. B = 56°, b = 17, c = 14
Law of Sines: C = arcsin[c·sinB/b] ≅43.1°
A = 180-B-C = 80.9°
Law of Sines: a = b·sinA/sinB ≅ 20.2
B1. B = 116°, a = 11, c = 15
Law of Cosines: b = √(a² + c² - 2ac·cosB) = 22.2
A = arccos{(b²+c²-a²)/(2bc) ≅26.5°
C = 180-A-B = 37.5°
B2. a=18, b=29, c=30
Law of Cosines: A = arccos{(b²+c²-a²)/(2bc) ≅ 35.5°
Law of Cosines: B = arccos[(a²+c²-b²)/(2ac) = 69.2°
C = 180-A-B = 75.3°
The answer is 7x+7/x^2+3x-10
