Answer: s > 5
Step-by-step explanation:
-s² + 25s - 100 > 0
Coefficient of s² is -1, multiply the equation through by -1.
-1 × (-s² + 25s - 100)
s² — 25s + 100
ax² + bx + c
Then you get the factors x and y that gives x + y = b and xy = c
b = -25 and c = 100, x = -20 and y = -5
-20 × -5 = 100 and -20 + -5 = -25
Then
s² — 20s — 5s + 100 > 0
Factorising,
s (s — 20) — 5(s — 20) > 0
(s — 5)(s — 20) > 0
(s — 5) > 0 and (s — 20) > 0
s>5 and s>20
s > 5
Hope this Helps?
Answer:
(a) even function
(b) odd function
Step-by-step explanation:
From the given information;
Any function x(t) can be said to be the sum of even and odd functions.
i.e.
where;
x(t) is a real function.
For a real and even function, the Fourier transform is also real and even.
Also, the Fourier Transform of a real and odd function is imaginary and odd.
The behavior of X(f) largely depends on the behavior of x(t).
If x(t) is real and even, then x(f) is real and even valued function
Thus, the real part of X(f) is an even function.
If x(t) is real and odd, then x(f) is imaginary and odd valued function
Thus, the imaginary part of X(f) is an odd function.
Answer: 30, D
Area of rectangle = 4*6=24
Area of triangle = 4*3/2 = 6
24+6?30
Answer:
Step-by-step explanation:
finding PR ( public relations :D , not that PR , the PR on this triangle thingy )
use law of cosines, again
c=sq rt [ a^2+b^2﹣2*a*b*cos(C) ]
where
c=PR
a= 9
b = 22
C = the angle of Q or 180 = 97+24+Q so Q = 180-97-24 = 59°
they tried to trick us.. by not giving us the angle C for the above cosine formula , but we figured out their diabolical plan :D yay super hero math
then
PR = sq rt [ 9^2 + 22^2 - 2*9*22*cos(59) ]
PR = sq rt [ 81 + 484 -203.9550777 ]
( notice that now it is a subtraction sign instead of a plus sign, this time? )
PR = sq rt [361.0449 ]
PR = 19.0011
to the nearest 10th
19.0 :)
