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mafiozo [28]
2 years ago
7

Which raises can be represented by algebraic expression 2x + 1 check all that apply

Mathematics
1 answer:
RoseWind [281]2 years ago
6 0

Answer:

two times a number plus 1

Step-by-step explanation:

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The relation of 10 squares to 100 squares can be expressed in many ways. Which of the following is not a way to express the rela
irakobra [83]

Answer:

As there are no options given in the question, but the options in the complete question are;

a) 2/10b) 20%c) 0.02d) 0.2

So, from the given options "c" is not a way to express this.

we can write 20/100 as 2/10 so option a is a way to express given relationship. and if we look at option b, it is also a way to express 20 from 100 is 20%. And if we divide, we get 20/100 = 2/10 = 0.2, so d is also a way to express given relationship. Thus, c is the answer.

Step-by-step explanation:As there are no options given in the question, but the options in the complete question are;

a) 2/10b) 20%c) 0.02d) 0.2

So, from the given options "c" is not a way to express this.

we can write 20/100 as 2/10 so option a is a way to express given relationship. and if we look at option b, it is also a way to express 20 from 100 is 20%. And if we divide, we get 20/100 = 2/10 = 0.2, so d is also a way to express given relationship. Thus, c is the answer.

3 0
2 years ago
Read 2 more answers
Find the area of the trapezoid.​
BaLLatris [955]

Answer:

32.5cm squared

Step-by-step explanation:

((4+9)/2)·5=32.5

3 0
3 years ago
Find the value of the constant m √150 - √12m + √54 = 0​
Tomtit [17]

Answer:

<u>m</u><u> </u><u>is</u><u> </u><u>√</u><u>2</u>

Step-by-step explanation:

{ \tt{ \sqrt{150}  -  \sqrt{12}m +  \sqrt{54}  = 0 }} \\ { \tt{ \sqrt{12}m } =  \sqrt{150}  -  \sqrt{54} } \\ { \tt{ (\sqrt{4 \times 3}) m = ( \sqrt{25 \times 6} ) - ( \sqrt{9 \times 6}) }} \\ { \tt{( \sqrt{4 \times 3} )m = 5 \sqrt{6}  - 3 \sqrt{6} }} \\ { \tt{2 \sqrt{3}m = 5 \sqrt{6}   - 3 \sqrt{6} }} \\ { \tt{2 \sqrt{3} m = 2 \sqrt{6} }} \\ { \tt{ \sqrt{3}  m =  \sqrt{6} }} \\ { \tt{ \sqrt{3} m = ( \sqrt{3} \times  \sqrt{2} ) }} \\ { \tt{m =  \sqrt{2} }}

7 0
3 years ago
An integer N is to be selected at random from {1, 2, ... , (10)3 } in the sense that each integer has the same probability of be
Andrej [43]

Answer:

Probability of N Divisible by 3 - 0.33

Probability of N Divisible by 5 - 0.2

Probability of N Divisible by 7 - 0.413

Probability of N Divisible by 15 - 0.066

Probability of N Divisible by 105 - 0.0095

Step-by-step explanation:

Given data:

Integer N {1,2,.....10^3}

Thus total number of ways by which 1000 is divisible by 3 i.e. 1000/3 = 333.3

Probability of N divisible by 3 {N%3 = 0 } = \frac{333.3}{1000} = 0.33

total number of ways by which 1000 is divisible by 5 i.e. 1000/5 = 200

Probability of N divisible by 5 {N%5 = 0 } = \frac{200}{1000} = 0.2

total number of ways by which 1000 is divisible by 7 i.e. 1000/7 = 142.857

Probability of N divisible by 7 {N%7 = 0 } = \frac{142.857}{1000} = 0.413

total number of ways by which 1000 is divisible by 15 i.e. 1000/15 = 66.667

Probability of N divisible by 15 {N%15 = 0 } = \frac{66.667}{1000} = 0.066

total number of ways by which 1000 is divisible by 105 i.e. 1000/105 = 9.52

Probability of N divisible by 105 {N%105 = 0 } = \frac{9.52}{1000} = 0.0095

similarly for N is selected from 1,2.....(10)^k where K is  large then the N value. Therefore effect of k will remain same as previous part.

3 0
3 years ago
Read 2 more answers
PLEASE HELP QUICKLY: GEOMETRY
WITCHER [35]

x/230=43/215

your answer would be 46

7 0
3 years ago
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