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2 years ago

Help plzzzzzzzzzzzzzzzzzzzzzz

Mathematics

1 answer:

lianna [129]2 years ago

3 0

No because 7-4 would be 3, then 3/3 is just 1 so the answer would be x=1

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2 years ago

Solve using long division <br> Please

madreJ [45]

1. $Solution,\frac{2x^3+4x^2-5}{x+3}:\quad 2x^2-2x+6-\frac{23}{x+3}$

$Steps:$

$\mathrm{Divide}\:\frac{2x^3+4x^2-5}{x+3}:\quad \frac{2x^3+4x^2-5}{x+3}=2x^2+\frac{-2x^2-5}{x+3}$

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$\mathrm{The\:Correct\:Answer\:is\:2x^2-2x+6-\frac{23}{x+3}}$

2. $Solution, \frac{4x^3-2x^2-3}{2x^2-1}:\quad 2x-1+\frac{2x-4}{2x^2-1}$

$Steps:$

$\mathrm{Divide}\:\frac{4x^3-2x^2-3}{2x^2-1}:\quad \frac{4x^3-2x^2-3}{2x^2-1}=2x+\frac{-2x^2+2x-3}{2x^2-1}$

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$\mathrm{The\:Correct\:Answer\:is\:2x-1+\frac{2x-4}{2x^2-1}}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

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2 years ago

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vichka [17]

Answer:

21.92

Step-by-step explanation:

division

87.68 ÷ 4

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2 years ago

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Which is the correct solution to ‐3x<21?

elena-s [515]

Top right
this is because, when dividing an inequality by a negative number, you must flip the inequality sign

-3x < 21
x > -7

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2 years ago

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