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EastWind [94]
2 years ago
6

How much would $400 be worth after 6 years if it was invested at 2% interest compounded annually

Mathematics
2 answers:
kari74 [83]2 years ago
5 0
<h2>Answer:</h2>

450.46497

<h3></h3><h2>Step-by-step explanation:</h2><h3>Based on the given condition:</h3>

We\ know\ that:

\left\{\begin{matrix}P=400\\r=2\%\\n=1\\t=6\\\end{matrix}\right.

________________________________________________

<h3>Formulate and substitute:</h3>

Substitute \left\{\begin{matrix}P=400\\r=2\%\\n=1\\t=6\\\end{matrix}\right.into\ formula

F=P*(1+r/n)^n^t\\ F=400\bullet(1+2\bullet\frac{1}{100})^6

_________________________________________________

<h3>Evaluate</h3>

Evaluate\ the\ equation/expression:\\ 450.46497

<em>I hope this helps you</em>

<em>:)</em>

Alexxx [7]2 years ago
4 0
P=400 (your amount invested)
r=.02 (rate as a decimal)
n=1 (number of times compounded per year, annually meaning 1)
t=6 (number of years invested)

you must follow orders of operations when you plug these things in your calculator.
1st step) do .02/1 to get 0.2 then add 1 to get 1.02. raise this to (1*6)and you get roughly 1.126, now multiply this by 400 to get answer D 450.46.
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A researcher wishes to​ estimate, with 9090​% ​confidence, the proportion of adults who have​ high-speed Internet access. Her es
Sunny_sXe [5.5K]

Answer:  a) Required minimum sample size= 219

b) Required minimum sample size= 271

Step-by-step explanation:

As per given , we have

Margin of error : E= 5% =0.05

Critical z-value for 90% confidence interval : z_{\alpha/2}=1.645

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Formula to find the sample size :-

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.28(1-0.28)(\dfrac{1.645}{0.05})^2\\\\=218.213856\approx219

Required minimum sample size= 219

b) If no estimate of true proportion is given , then we assume p= 0.5

Formula to find the sample size :-

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Required minimum sample size= 271

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Answer:

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Step-by-step explanation:

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Problems of normal distributions can be solved using the z-score formula.

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Z = \frac{X - \mu}{\sigma}

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This means that \mu = 6, \sigma = 0.4

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This is X when Z has a p-value of 0.9, so X when Z = 1.28. Then

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X = 6.512

The 90th percentile of the distribution is 6.512 ml.

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