Answer:
hmmm...? im gonna guess 2
Step-by-step explanation:
i finger plus another finger gives me......ahhhhh ik the answer its 2
Sin2x=2sinxcosx, cos2x=1-2sin^2x
sin(2x)+cos(3x)=2sinxcosx+cos(x+2x)
cos(x+2x)=cosx(1-2sin^2(x))-sinx2sinxcosx
sin(2x)+cos(3x)=2sinxcosx(1-sinx)+cosx(1-2sin^2(x))
Answer is d
it would be b^12