Answer:
Interval of 50 on both axis
Step-by-step explanation:
Given
There are several ways to do this, but I will use the observation method, since the dataset is small.
Considering the x-coordinates
Each element of the data set is a multiple of 50.
Hence, an interval of 50 can be used on the x-axis
Considering the y-coordinates
Each element of the data set is a multiple of 50.
Hence, an interval of 50 can be used on the y-axis
<em>So, an interval of 50 can be used on both axes</em>
Answer:
<u>1.16 m (approximately)</u>
Step-by-step explanation:
Let x be the width of the path.
Total area = (5+2x)(3+2x) = 39
Expand and simplify
4x²+ 16x+15-39 = 0
4x² + 16x - 24 = 0
Simplify
x² + 4x -6 = 0
Rational factoring does not work, so use quadratic formula
x = +/- sqrt(10) -2
= 1.16 or -5.16 (reject)
= <u>1.16 m (approximately)</u>
C. grades in courses because it depends on how much the students study to get their grades
Answer:
(
−
5
)
(
−
4
)
Step-by-step explanation:
Not 100 percent sure
Answer:
V = πr³ + 2πr²
Step-by-step explanation:
Volume of a cylinder:
V = πr²h
with radius r and height h = 2 + r:
V = πr²(2 + r) = πr³ + 2πr²
