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kotegsom [21]
3 years ago
14

Sara uses a scale of 1 cm : 12 m to draw a floor plan of a

Mathematics
1 answer:
sweet [91]3 years ago
8 0
The correct answer is B. So for A, 8m is smaller than 12 m. For B, 20 m is Bigger. For C, Find how many meters is 1 centimeter, the answer is 1 cm : 12m, the meter is not bigger than 12, but the same, so C is wrong. For D, divide both sides by 3 to find 1 CM, the answer is 1 cm : 5 m, it is wrong.
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A family of 4 spent $104 for tickets to a concert on Friday and they spent $140 for tickets to a dinner theater on Saturday. All
Julli [10]

Answer:

  • Friday's tickets: $26 each
  • Saturday's tickets: $35 each

Step-by-step explanation:

We presume that 4 tickets were bought each day, so the price of 1 ticket is 1/4 of the total price:

  (1/4)($104) = $26

  (1/4)($140) = $35

The cost of each ticket on Friday was $26; on Saturday, the cost was $35.

5 0
3 years ago
Completing the square: x^2-18x=-34
balu736 [363]
X^2-18x__=-34
X^2-18x+(18/2)^2=-34
X^2-18x+81=-34+81
(X+9)^2=47
(X+9)^2-47=0
3 0
3 years ago
According to the Rational Root Theorem, which number is a potential root of f(x) = 9x8 + 9x6 – 12x + 7?
AysviL [449]

Answer:

\pm 1, \pm\dfrac{1}{3},\pm\dfrac{1}{9},\pm 7, \pm\dfrac{7}{3},\pm\dfrac{7}{9}.

Step-by-step explanation:

According to the Rational Root Theorem, the potential roots of a polynomial are

x=\pm\dfrac{p}{q}  

where, p is a factor of constant and q is a factor of leading term.

The given polynomial is

f(x)=9x^8+9x^6-12x+7

Here, 9 is the leading term and 7 is constant.

Factors of 9 are ±1, ±3, ±9.

Factors of 7 are ±1, ±7.

Using rational root theorem, the rational or potential roots are

x=\pm 1, \pm\dfrac{1}{3},\pm\dfrac{1}{9},\pm 7, \pm\dfrac{7}{3},\pm\dfrac{7}{9}

Therefore, the potential root of f(x) are \pm 1, \pm\dfrac{1}{3},\pm\dfrac{1}{9},\pm 7, \pm\dfrac{7}{3},\pm\dfrac{7}{9}.  

4 0
3 years ago
Read 2 more answers
Use the Divergence Theorem to calculate the surface integral S F · dS; that is, calculate the flux of F across S. F(x, y, z) = x
devlian [24]

Answer:

-14 / 3

Step-by-step explanation:

- Divergence theorem, expresses an explicit way to determine the flux of a force field ( F ) through a surface ( S ) with the help of "del" operator ( D ) which is the sum of spatial partial derivatives of the force field ( F ).

- The given force field as such:

                      F = (x^2y) i + (xy^2) j + (3xyz) k

Where,

         i, j, k are unit vectors along the x, y and z coordinate axes, respectively.

- The surface ( S ) is described as a tetrahedron bounded by the planes:

                      x = 0 \\y = 0\\x + 2y + z = 2

                      z = 0\\

- The divergence theorem gives us the following formulation:

                      _S\int\int {F} \,. dS = _V\int\int\int {D [F]} \,. dV

- We will first apply the del operator on the force field as follows:

                      D [ F ] = 2xy + 2xy + 3xy = 7xy

- Now, we will define the boundaries of the solid surface ( Tetrahedron ).

- The surface ( S ) is bounded in the z - direction by plane z = 0 and the plane [ z = 2 - x - 2y ]. The limits of integration for " dz " are as follows:

                      dz: [ z = 0 - > 2 - x - 2y ]

- Now we will project the surface ( S ) onto the ( x-y ) plane. The projection is a triangle bounded by the axes x = y = 0 and the line: x = 2 - 2y. We will set up our limits in the x- direction bounded by x = 0 and x = 2 - 2y. The limits of integration for " dx " are as follows:

                     dx: [ x = 0 - > 2 - 2y ]

- The limits of "dy" are constants defined by the axis y = 0 and y = -2 / -2 = 1. Hence,

                    dy: [ y = 0 - > 1 ]

- Next we will evaluate the triple integral as follows:

                   \int\int\int ({D [ F ] }) \, dz.dx.dy = \int\int\int (7xy) \, dz.dx.dy\\\\\int\int (7xyz) \, | \limits_0^2^-^x^-^2^ydx.dy\\\\\int\int (7xy[ 2 - x - 2y ] ) dx.dy = \int\int (14xy -7x^2y -14 xy^2 ) dx.dy\\\\\int (7x^2y -\frac{7}{3} x^3y -7 x^2y^2 )| \limits_0^2^-^2^y.dy  \\\\\int (7(2-2y)^2y -\frac{7}{3} (2-2y)^3y -7 (2-2y)^2y^2 ).dy  \\\\

                 7 (-\frac{(2-2y)^3}{6} + (2-2y)^2 ) -\frac{7}{3} ( -\frac{(2-2y)^4}{8} + (2-2y)^3) -7 ( -\frac{(2-2y)^3}{6}y^2 + 2y.(2-2y)^2 )| \limits^1_0\\\\ 0 - [ 7 (-\frac{8}{6} + 4 ) -\frac{7}{3} ( -\frac{16}{8} + 8 ) -7 ( 0 ) ] \\\\- [ \frac{56}{3} - 14 ] \\\\\int\int {F} \, dS  = -\frac{14}{3}

3 0
3 years ago
You have a cylindrical pond that has a diameter of 30 feet and has a depth of 5 feet. If you need to fill the pond one-quarter o
Free_Kalibri [48]

Answer:It remains for naval architects to reconcile the discrepancy if they can. ... The artist has represented the - procession which, headed by President Grant and the ... These pipes are represented in the engraving at about 12 feet from the floor, and ... to the pond, but each less than one quarter its size, and having a smaller depth, ...

Mechanics

Step-by-step explanation:

3 0
4 years ago
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