43 < y - 30
add 30 to both sides
73 < y
y can be anything that is greater than 73
so it could be...
101, 74, 90, 75, 980767, 5674, etc.
Hope this helps!
Using the z-distribution, it is found that she should take a sample of 46 students.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:

The margin of error is:

In which:
is the sample mean.
is the standard deviation for the population.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
Scores on the math portion of the SAT are believed to be normally distributed and range from 200 to 800, hence, by the Empirical Rule the standard deviation is found as follows:



The sample size is n when M = 29, hence:





n = 45.67.
Rounding up, a sample of 46 students should be taken.
More can be learned about the z-distribution at brainly.com/question/25890103
#SPJ1
If there is an odd number of data values then the median will be the value in the middle. If there is an even number of data values the median is the mean of the two data values in the middle. For the data set 1, 1, 2, 5, 6, 6, 9 the median is 5. For the data set 1, 1, 2, 6, 6, 9 the median<span> is 4.
</span>The mean<span> is the average of the numbers: a calculated "central" value of a set of numbers. To calculate: Just add up all the numbers, then divide by how many numbers there are.</span><span>
</span>
Answer:
<h2><u><em>
n = 1/5m + (-2)/5</em></u></h2>
Step-by-step explanation:
-m + 5n = -2, for n
-m + 5n = -2
-m +5n + m = -2 + m
5n = m - 2
5n/5 = (m-2)/5
n = 1/5m + (-2)/5