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Crazy boy [7]
3 years ago
15

The stem-and-leaf plot lists the number of times different families visit the local zoo each year. How many families visit the z

oo at least 25 times, but fewer than 44 times each year? Enter your answer in the box. A stem-and-leaf plot with a stem value of 1 with a leaf value of 2, 2, 4, 5, 7, a stem value of 2 with a leaf value of 8, 9, a stem value of 3, a stem value of 4 with a leaf value of 0, 1, 4, 5, a stem value of 5 with a leaf value of 0, and a stem value of 6 with a leaf value of 9. Key: 1|2 means 12
Mathematics
1 answer:
Arada [10]3 years ago
7 0

Answer:

4

Step-by-step explanation:

The values listed in the stem and leaf plot are

12,12,14,15,17,28,29,40,41,44,45,50,69

The values that are at least 25 and less than 44 are

28,29,40,41

4 families

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Complete the square to re-write the quadratic function in vertex form: y=x2-x+3
Anna [14]

Answer:

Step-by-step explanation:

hello :

note : the vertex form is :

ax²+bx+c = a(x+(b)/(2a))²-  delta/4a²   and   delta = b²- 4ac

in this exercice you have : a =1    b = -1   and  c= 3

continu ..........

5 0
3 years ago
A father’s age now is three times the age that his son was 4 years ago. In
Mice21 [21]
Let ‘s’ be the son’s age 12 years ago.
Let ‘f’ be the father’s current age.

4 years ago, the son was:

s-4

So, his father is currently:

3(s-4)

=

3s-12

Therefore:

f = 3s-12

In twelve years, the son will be:

s+12

And the father will be:

f+12

This can also be written as:

3s-12+12 as the fathers younger age would be f = 3s+12

=

3s

So, we know that s+12 is half the fathers current age, meaning the father is currently 2(s+12) which is equivalent to 2s+24. Also, we know that the father is currently 3 times the sons age 12 years ago, so 3s (proven by the calculations we made above). Therefore, 2s+24=3s which means 24=s. We can then substitute this, and we will receive 24+12 = 36

Son’s current age: 36

We then substitute the son’s age 12 years ago into 2s+24 to give us the father’s age.

2(24)+24 = 72

Father’s current age: 72










7 0
2 years ago
Ryker wants a new car. The dealership offers him a loan at 9% annual interest for 6 years. If Ryker wants to do some calculation
Contact [7]

The monthly interest rate is 0.75%

<u>Step-by-step explanation:</u>

The rate of interest= 9%

Total time = 6years

Interest rate per month = 9/12

= 0.75%

Monthly payment =cost of the car + 0.75% of cost of car

Interest per month is 0.75%

3 0
3 years ago
Pls help me for once....
ryzh [129]
The answers are C and also D
3 0
3 years ago
Suppose that a brand of lightbulb lasts on average 1730 hours with a standard deviation of 257 hours. Assume the life of the lig
Debora [2.8K]

Answer:

P [  1689  ≤   X  ≤  2267 ]  = 54,88 %

Step-by-step explanation:

Normal Distribution

Mean        μ₀  =  1730

Standard Deviation      σ  = 257

We need to calculate  z scores for the values   1689     and      2267

We apply formula for z scores

z =  ( X -  μ₀ ) /σ

X = 1689     then

z = (1689 - 1730)/ 257      ⇒ z = - 41 / 257

z  = -  0.1595

And from z table we get  for  z =  - 0,1595

We have to interpolate

        - 0,15          0,4364

        - 0,16          0,4325

Δ  =   0.01           0.0039

0,1595  -  0,15  =  0.0095

By rule of three

0,01                  0,0039

0,0095                 x ??      x  =  0.0037

And    0,4364  -  0.0037  = 0,4327

Then    P [ X ≤ 1689 ]  =  0.4327     or    P [ X ≤ 1689 ]  = 43,27 %

And for the upper limit  2267  z  score will be

z  =  ( X - 1730 ) / 257       ⇒  z =  537 / 257

z  =  2.0894

Now from z table   we find  for score   2.0894

We interpolate and assume  0.9815

P [ X ≤ 2267 ]  =  0,9815

Ths vale already contains th value of   P [ X ≤ 1689 ]  =  0.4327

Then we subtract  to get    0,9815  -  0,4327   = 0,5488

Finally

P [ 1689  ≤   X  ≤  2267 ]  =  0,5488  or  P [  1689  ≤   X  ≤  2267 ]  = 54,88 %

8 0
3 years ago
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