Answer:
The value of the proposition is FALSE
Step-by-step explanation:
~[(A ⊃ Y) v ~(X ⊃ B)] ⋅ [~(A ≡ ~X) v (B ⊃ X)]
Let's start with the smallest part: ~X. The symbol ~ is negation when X is true with the negation is false and vice-versa. In this case, ~X is true (T)
~[(A ⊃ Y) v ~(X ⊃ B)] ⋅ [~(A ≡ T) v (B ⊃ X)]
Now the parts inside parenthesis: (A ⊃ Y),(X ⊃ B),(A ≡ T) and (B ⊃ X). The symbol ⊃ is the conditional and A ⊃ Y is false when Y is false and A is true, in any other case is true. The symbol ≡ is the biconditional and A ≡ Y is true when both A and Y are true or when both are false.
(A ⊃ Y) is False (F)
(X ⊃ B) is True (T)
(A ≡ T) is True (T)
(B ⊃ X) is False (F)
~[(F) v ~(T)] ⋅ [~(T) v (F)]
The two negations inside the brackets must be taken into account:
~[(F) v F] ⋅ [F v (F)]
The symbol left inside the brackets v is the disjunction, and A v Y is false only with both are false. F v (F) is False.
~[F] ⋅ [F]
Again considerating the negation:
T⋅ [F]
Finally, the symbol ⋅ is the conjunction, and A v Y is true only with both are true.
T⋅ [F] is False.
Answer:
48
Step-by-step explanation:
(2*6)4
(12)4
48
Hoped it helped :)
So the first hour it travels from 1-6 miles, the second hour it travels at least two miles. And the question is "draw the range of miles the boat could of traveled in the second hour". Well first of all the third hour is completely useless so forget about that. Now, the first hour says it traveled from 1-6 miles, we don't know how many miles it traveled for sure but it could of traveled up to 6. So in the second hour when they say "at least two miles" the boat could of travled at least two miles more than 1-6. So 1+2+3, 2+2+4, 3+2=5, 4+2=6, 5+2=7 and 6+2=8. So the boat could of traveled from 3 to 8 miles in the second hour.
The answers to the questions are C=11 and D=3
